The condition of one mole of an ideal gas in a closed container changes from (T1-800K, P1=1 bar, V1) to (T2, P2=0.5 bar, V2=0.5V1), using the following two-step processes: 1a- 2: Isobaric Process(i.e., constant P) Process (a): 11a: Isochoric Process (i.e., constant V) 1b 2: Isochoric Process (i.e., constant V) Process (b): 11b: Isobaric Process(i.e., constant P) T1b Determine: T1a= T2= 5 Fill the following Table (with units) Note: Cy R 2 2 AU Process W 1 1a 1a 2 192 (process a) 1-1b 1b 2 192 (process b)
The condition of one mole of an ideal gas in a closed container changes from (T1-800K, P1=1 bar, V1) to (T2, P2=0.5 bar, V2=0.5V1), using the following two-step processes: 1a- 2: Isobaric Process(i.e., constant P) Process (a): 11a: Isochoric Process (i.e., constant V) 1b 2: Isochoric Process (i.e., constant V) Process (b): 11b: Isobaric Process(i.e., constant P) T1b Determine: T1a= T2= 5 Fill the following Table (with units) Note: Cy R 2 2 AU Process W 1 1a 1a 2 192 (process a) 1-1b 1b 2 192 (process b)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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
Transcribed Image Text:The condition of one mole of an ideal gas in a closed container changes from (T1-800K, P1=1 bar,
V1) to (T2, P2=0.5 bar, V2=0.5V1), using the following two-step processes:
1a- 2: Isobaric Process(i.e., constant P)
Process (a): 11a: Isochoric Process (i.e., constant V)
1b 2: Isochoric Process (i.e., constant V)
Process (b): 11b: Isobaric Process(i.e., constant P)
T1b
Determine: T1a=
T2=
5
Fill the following Table (with units) Note: Cy
R
2
2
AU
Process
W
1 1a
1a 2
192 (process a)
1-1b
1b 2
192 (process b)
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