The concentration of a NaOH solution is determined in a single experiment by titrating a weighed sample of pure, dried KHP (MW = 204.229) with the NaOH. The data are: Weight of KHP = (11.6723 +0.0001) (10.8364 ± 0.0001) g Volume NaOH = (32.68 ± 0.02) - (1.24 ± 0.02) mL - Where the standard deviations are o values. (a) What is the molarity of the NaOH? (b) Based on the propagation-of-error formula, what is the standard deviation of the molarity,OM?
The concentration of a NaOH solution is determined in a single experiment by titrating a weighed sample of pure, dried KHP (MW = 204.229) with the NaOH. The data are: Weight of KHP = (11.6723 +0.0001) (10.8364 ± 0.0001) g Volume NaOH = (32.68 ± 0.02) - (1.24 ± 0.02) mL - Where the standard deviations are o values. (a) What is the molarity of the NaOH? (b) Based on the propagation-of-error formula, what is the standard deviation of the molarity,OM?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The concentration of a NAOH solution is determined in a single experiment by titrating a weighed
sample of pure, dried KHP (MW = 204.229) with the NaOH. The data are:
Weight of KHP = (11.6723 ± 0.0001) - (10.8364 ± 0.0001) g
= (32.68 ± 0.02) – (1.24 ± 0.02) mL
%3D
Volume NaOH
Where the standard deviations are o, values. (a) What is the molarity of the NaOH?
(b) Based on the propagation-of-error formula, what is the standard deviation of the molarity,on ?
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