The computation of the t-statistic was held in four phases. First, the SS was extracted from the standard deviation (s) formula s = The SS for group I was computed as 3.6992 from the formula 0.34 = The SS for group 2 was computed as 2.5725 from the formula 0.35 = Second, the pooled variance (s) of 0.1183 was obtained using the formula: s3 = 3.6992+2.5725 6.2717 = 0.1183. 32+21 53 SS1 + SS2 df₁+df₂ Third, the estimated standard error for the mean differences (S(M1-M2)) of 0.09466 wa computed using the formula: S(M1-M2) 0.09466. $²2- 121 12₂ 0.1183 33 0.1183 22 = 0.008962 =

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  Traditional Students (G1) Online Students (G2)
mean 2.97 2.95
standard deviation 0.34 0.35
sample size 33 22

significance level: 0.05

degree of freedom: 53

#1) Fix the errors seen in the image below.

IX. T-Statistic Calculation
The computation of the t-statistic was held in four phases.
First, the SS was extracted from the standard deviation (s) formula s =
The SS for group 1 was computed as 3.6992 from the formula 0.34 =
The SS for group 2 was computed as 2.5725 from the formula 0.35 =
0.09466.
Second, the pooled variance (s) of 0.1183 was obtained using the formula: s =
3.6992+2.5725
SS₁ + SS₂
df₁+df₂
= 0.1183.
32+21
Third, the estimated standard error for the mean differences (S(M1-M2)) of 0.09466 was
0.1183 0.1183
+
33
22
computed using the formula: S(M1-M2) =
t =
=
X. P-Value
6.2717
53
Fourth, the t-statistic of 0.2112 is obtained, as shown below:
(M₁-M₂)-(H₁-H₂) 2.97-2.95-0
S(M1-M2)
0.09466
=
=
+ =
n1 n2
0.02
0.09466
SS
= 0.2112.
SS
32
21
= √0.008962 =
The p-value was obtained using the t-distribution table
The sample
sizes of the two groups were 33 and 22, and the degree of freedom was 53. To find the p-
value, it is necessary to look at the row corresponding to 53 at a significance level of 0.05
and two tails. The value of the critical test statistic is 2. The computed t-statistic, 0.2112,
falls between 0 and 0.679 from the same row. The next step is to look at the alpha levels
at the top of the table with two tails, corresponding to 0 and 0.679. These alpha levels are
1 and 0.5. Therefore, the p-value of the test, which is 0.75, will be between 1 and 0.5. The
p-value was confirmed using the TI-84 obtaining a similar p-value of 0.7994.
Transcribed Image Text:IX. T-Statistic Calculation The computation of the t-statistic was held in four phases. First, the SS was extracted from the standard deviation (s) formula s = The SS for group 1 was computed as 3.6992 from the formula 0.34 = The SS for group 2 was computed as 2.5725 from the formula 0.35 = 0.09466. Second, the pooled variance (s) of 0.1183 was obtained using the formula: s = 3.6992+2.5725 SS₁ + SS₂ df₁+df₂ = 0.1183. 32+21 Third, the estimated standard error for the mean differences (S(M1-M2)) of 0.09466 was 0.1183 0.1183 + 33 22 computed using the formula: S(M1-M2) = t = = X. P-Value 6.2717 53 Fourth, the t-statistic of 0.2112 is obtained, as shown below: (M₁-M₂)-(H₁-H₂) 2.97-2.95-0 S(M1-M2) 0.09466 = = + = n1 n2 0.02 0.09466 SS = 0.2112. SS 32 21 = √0.008962 = The p-value was obtained using the t-distribution table The sample sizes of the two groups were 33 and 22, and the degree of freedom was 53. To find the p- value, it is necessary to look at the row corresponding to 53 at a significance level of 0.05 and two tails. The value of the critical test statistic is 2. The computed t-statistic, 0.2112, falls between 0 and 0.679 from the same row. The next step is to look at the alpha levels at the top of the table with two tails, corresponding to 0 and 0.679. These alpha levels are 1 and 0.5. Therefore, the p-value of the test, which is 0.75, will be between 1 and 0.5. The p-value was confirmed using the TI-84 obtaining a similar p-value of 0.7994.
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