6 ftThe composite shaft shown consists of a 0.2-in.-thick brassjacket (G = 5.6 × 10° psi) bonded to a 1.2-in.-diameter steel core(Gsteel = 11.2 x 10° psi). Knowing that the shaft is subjected to5-kip · in. torques, determine (a) the maximum shearing stress inthe brass jacket, (b) the maximum shearing stress in the steelcore, (c) the angle of twist of end B relative to end A.TBBrass jacket1.2 in.- Steel core0.2 in.

Given : A composite shaft consist of 2 in thick brass jacket. Diameter of steel core is ,d=1.2 in.…

Answered: The composite shaft shown consists of a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

100%

6 ft
The composite shaft shown consists of a 0.2-in.-thick brass
jacket (G = 5.6 × 10° psi) bonded to a 1.2-in.-diameter steel core
(Gsteel = 11.2 x 10° psi). Knowing that the shaft is subjected to
5-kip · in. torques, determine (a) the maximum shearing stress in
the brass jacket, (b) the maximum shearing stress in the steel
core, (c) the angle of twist of end B relative to end A.
T
B
Brass jacket
1.2 in.
- Steel core
0.2 in.

Expert Solution

Step 1

Given :

A composite shaft consist of 2 in thick brass jacket.
Diameter of steel core is ,d=1.2 in.
The shaft is subjected torque ,T=5 kip $\cdot$ in
Inner diameter of brass is d=1.2 in.
Outer diameter of brass jacket D=1.2 in+0.4 in =1.6 in .
Modulus of rigidity of the brass is, G _brass=5.6 $\times$ 10⁶psi.
Modulus of rigidity of brass is ,G_steel=11.2 $\times$ 10⁶ psi.

Part a:

The formula of maximum shear stress in brass jacket given by:

$\begin{array}{rcl} \frac{T}{J} & = & \frac{ζ}{R} \\ ζ & = & \frac{T}{J} R \\ = & \frac{T}{\frac{π}{32} (D^{4} - d^{4})} \times (\frac{D}{2}) \\ Substitute the value in given equation \\ = & \frac{5 kip \cdot in}{\frac{π}{32} (1 . 6^{4} {in}^{4} - 1 . 2^{4} {in}^{4})} \times (\frac{1.6 in}{2}) \\ = & 9.094 \frac{kip}{{in}^{2}} \end{array}$

Therefore maximum shear stress in the brass jacket is 9.094 kip/in² .

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions