## Induced Current in a Circular Coil**Problem Statement:**The component of the external magnetic field along the central axis of a 33 turn circular coil of radius 27.0 cm decreases from 1.90 T to 0.400 T in 2.90 s. If the resistance of the coil is \( R = 6.00 \, \Omega \), what is the magnitude of the induced current in the coil?- **Magnitude:** \( \boxed{} \, \text{A} \)### Direction of the Induced Current:- What is the direction of the current if the axial component of the field points away from the viewer? - [ ] Counter-clockwise - [ ] Clockwise### Explanation:To find the induced current in the coil, we use Faraday's Law of Induction which states that the induced electromotive force (emf) in the coil is given by:\[ \mathcal{E} = -N \frac{d\Phi_B}{dt} \]Where:- \( N \) is the number of turns- \( \Phi_B \) is the magnetic flux- \( \frac{d\Phi_B}{dt} \) is the rate of change of magnetic fluxThe magnetic flux \( \Phi_B \) through one turn of the coil is given by:\[ \Phi_B = B \cdot A \]Where:- \( B \) is the magnetic field- \( A \) is the area of the coil (\( A = \pi r^2 \))Given data:- \( N = 33 \)- \( r = 27.0 \, \text{cm} = 0.270 \, \text{m} \)- \( B \) changes from \( 1.90 \, \text{T} \) to \( 0.400 \, \text{T} \) in \( 2.90 \, \text{s} \)- \( R = 6.00 \, \Omega \)The change in magnetic flux \( \Delta \Phi_B \) is:\[ \Delta \Phi_B = \Phi_B (\text{final}) - \Phi_B (\text{initial}) \]\[ \Delta \Phi_B = (0.400 \, \text{T} \cdot \pi \cdot (0

Number of turns N = 33 Radius r = 27.0 cm = 0.27 m Change in magnetic field B = 1.90 T - 0.400 T =…

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