The complete decimation-in-frequency algorithm is depicted for N = 16; x[O]=x[2]=x[4]=x[6]=x[8]=x[10]=x[12]=x[14]=1 ( x[n] = 1 whenn is even number) ; x[1]=x[3]=x[5]=x[7]=x[9]=x[11]=x[13]=x[15]= -1 (x[n] = -1 when n is odd number . Draw the 16- element decimation in frequency for N = 16 and Calculate X[9] and X[15]. for the value of the line between each node, it should be always -1 and %D The graph is an example of an 16-element decimation-in-frequency. STAGE 1 STAGE 2 STAGE 3 + STAGE 4 00 000 10 0 08 20 04 30 O -O12 400 02 50 0 O 10 6 0 06 O 14 10 OO 0-05 110-O O 13 12 OO 03 13 O0 0 011 14 O 007 15 OO 0 O 15
The complete decimation-in-frequency algorithm is depicted for N = 16; x[O]=x[2]=x[4]=x[6]=x[8]=x[10]=x[12]=x[14]=1 ( x[n] = 1 whenn is even number) ; x[1]=x[3]=x[5]=x[7]=x[9]=x[11]=x[13]=x[15]= -1 (x[n] = -1 when n is odd number . Draw the 16- element decimation in frequency for N = 16 and Calculate X[9] and X[15]. for the value of the line between each node, it should be always -1 and %D The graph is an example of an 16-element decimation-in-frequency. STAGE 1 STAGE 2 STAGE 3 + STAGE 4 00 000 10 0 08 20 04 30 O -O12 400 02 50 0 O 10 6 0 06 O 14 10 OO 0-05 110-O O 13 12 OO 03 13 O0 0 011 14 O 007 15 OO 0 O 15
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![The complete decimation-in-frequency
algorithm is depicted for N = 16;
x[0]=x[2]=x[4]=x[6]=x[8]=x[10]=x[12]=x[14]=1 (
x[n] = 1 whenn is even number) ;
X[1]=x[3]=x[5]=x[7]=x[9]=x[11]=x[13]=x[15]= -1
(x[n] = -1 when n is odd number . Draw the 16-
element decimation in frequency for N = 16 and
Calculate X[9] and X[15]. for the value of the line
between each node, it should be always -1 and
1
The graph is an example of an 16-element
decimation-in-frequency.
STAGE 1
STAGE 2
STAGE 3
+STAGE 4-
000
10
O 8
20-0
30
O 12
40 O
0 O 2
50
OO 10
6 0-O
0 6
70
O 14
8 0
O 01
009
10 O
0 05
110O
0O 13
12 O
0 O 3
13 O 0
0O 11
14 O O
007
15 O O
-O 15
Signal flow graph for 16-point Decimation in Frequency FFT algorithm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf6c446e-50c8-4d83-a77c-d383b505b1f1%2Ff01c8ab2-cbf0-4af6-bf07-6bb63f587eba%2Fp89f8yc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The complete decimation-in-frequency
algorithm is depicted for N = 16;
x[0]=x[2]=x[4]=x[6]=x[8]=x[10]=x[12]=x[14]=1 (
x[n] = 1 whenn is even number) ;
X[1]=x[3]=x[5]=x[7]=x[9]=x[11]=x[13]=x[15]= -1
(x[n] = -1 when n is odd number . Draw the 16-
element decimation in frequency for N = 16 and
Calculate X[9] and X[15]. for the value of the line
between each node, it should be always -1 and
1
The graph is an example of an 16-element
decimation-in-frequency.
STAGE 1
STAGE 2
STAGE 3
+STAGE 4-
000
10
O 8
20-0
30
O 12
40 O
0 O 2
50
OO 10
6 0-O
0 6
70
O 14
8 0
O 01
009
10 O
0 05
110O
0O 13
12 O
0 O 3
13 O 0
0O 11
14 O O
007
15 O O
-O 15
Signal flow graph for 16-point Decimation in Frequency FFT algorithm
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