The commute distances at a huge corporation vary from employee to employee. It is known that the population of all these employee commute distances is approximately normally distributed. The corporation claims that the standard deviation of this population is 6.91 km. You are a recruiter who wants to test this claim with a random sample of 33 employees. Based on your sample, follow the steps below to construct a 95% confidence interval for the population standard deviation of all the employee commute distances. Then state whether the confidence interval you construct contradicts the corporation's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Take Sample Number of employees 33 Sample standard Sample mean Sample variance deviation 19.42 4.88 23.8144 To find the confidence interval for the population standard deviation, first find the confidence interval for the population variance. Enter the values of the point estimate of the population variance, the sample size, the left critical value, and the right critical value you need for your 95% confidence interval for the population variance. (Choose the correct critical values from the table of critical values provided.) When you are done, select "Compute". Point estimate of the population variance: Sample size: 95% confidence interval for the population variance: Critical values Left critical value: ☐ Right critical value: 95% confidence interval for the population standard deviation: Compute Left Right X.995-15.134 0.005 -56.328 X0.975 18.291.025 =49.48 X0.950 20.072.050 46.194 (b) Based on your sample, graph the 95% confidence interval for the population standard deviation of all the employee commute distances. • Enter the values for the lower and upper limits on the graph to show your confidence interval. Round the values to two decimal places. • For the point (*) enter the claim 6.91 made by the corporation on your graph. 95% confidence interval for the population standard deviation: (c) 0.00 0.00 2.00 4.00 5.00 10.00 6.00 8.00 10.00 Does the 95% confidence interval you constructed contradict the corporation's claim? Choose the best answer from the choices below. ○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is inside the 95% confidence interval. ○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is outside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is inside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is outside the 95% confidence interval.

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The commute distances at a huge corporation vary from employee to employee. It is known that the population of all these employee commute distances is
approximately normally distributed. The corporation claims that the standard deviation of this population is 6.91 km. You are a recruiter who wants to test this
claim with a random sample of 33 employees.
Based on your sample, follow the steps below to construct a 95% confidence interval for the population standard deviation of all the employee commute
distances. Then state whether the confidence interval you construct contradicts the corporation's claim. (If necessary, consult a list of formulas.)
(a) Click on "Take Sample" to see the results from the random sample.
Take Sample
Number of employees
33
Sample standard
Sample mean
Sample variance
deviation
19.42
4.88
23.8144
To find the confidence interval for the population standard deviation, first find the confidence interval for the population variance.
Enter the values of the point estimate of the population variance, the sample size, the left critical value, and the right critical value you need for your
95% confidence interval for the population variance. (Choose the correct critical values from the table of critical values provided.) When you are
done, select "Compute".
Point estimate of the
population variance:
Sample size:
95% confidence interval for the
population variance:
Critical values
Left critical value:
☐
Right critical value:
95% confidence interval for the
population standard deviation:
Compute
Left
Right
X.995-15.134 0.005 -56.328
X0.975 18.291.025 =49.48
X0.950 20.072.050 46.194
(b) Based on your sample, graph the 95% confidence interval for the population standard deviation of all the employee commute distances.
• Enter the values for the lower and upper limits on the graph to show your confidence interval. Round the values to two decimal places.
• For the point (*) enter the claim 6.91 made by the corporation on your graph.
95% confidence interval for the population standard deviation:
(c)
0.00
0.00
2.00
4.00
5.00
10.00
6.00
8.00
10.00
Does the 95% confidence interval you constructed contradict the corporation's claim?
Choose the best answer from the choices below.
○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is inside the 95%
confidence interval.
○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is outside the 95%
confidence interval.
Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is inside the 95%
confidence interval.
Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is outside the 95%
confidence interval.
Transcribed Image Text:The commute distances at a huge corporation vary from employee to employee. It is known that the population of all these employee commute distances is approximately normally distributed. The corporation claims that the standard deviation of this population is 6.91 km. You are a recruiter who wants to test this claim with a random sample of 33 employees. Based on your sample, follow the steps below to construct a 95% confidence interval for the population standard deviation of all the employee commute distances. Then state whether the confidence interval you construct contradicts the corporation's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Take Sample Number of employees 33 Sample standard Sample mean Sample variance deviation 19.42 4.88 23.8144 To find the confidence interval for the population standard deviation, first find the confidence interval for the population variance. Enter the values of the point estimate of the population variance, the sample size, the left critical value, and the right critical value you need for your 95% confidence interval for the population variance. (Choose the correct critical values from the table of critical values provided.) When you are done, select "Compute". Point estimate of the population variance: Sample size: 95% confidence interval for the population variance: Critical values Left critical value: ☐ Right critical value: 95% confidence interval for the population standard deviation: Compute Left Right X.995-15.134 0.005 -56.328 X0.975 18.291.025 =49.48 X0.950 20.072.050 46.194 (b) Based on your sample, graph the 95% confidence interval for the population standard deviation of all the employee commute distances. • Enter the values for the lower and upper limits on the graph to show your confidence interval. Round the values to two decimal places. • For the point (*) enter the claim 6.91 made by the corporation on your graph. 95% confidence interval for the population standard deviation: (c) 0.00 0.00 2.00 4.00 5.00 10.00 6.00 8.00 10.00 Does the 95% confidence interval you constructed contradict the corporation's claim? Choose the best answer from the choices below. ○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is inside the 95% confidence interval. ○ No, the confidence interval does not contradict the claim. The claimed standard deviation 6.91 is outside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is inside the 95% confidence interval. Yes, the confidence interval contradicts the claim. The claimed standard deviation 6.91 is outside the 95% confidence interval.
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