The combustion of pentene (C5H10) in the presence of oxygen gas will produce carbon dioxide and water vapor according to the chemical equation: 2 C5H10 + 15 02-10 CO₂ + 10 H₂O. How many grams of water will be produced if 248 g of pentene is burned in the presence of 319 g of oxygen gas?

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The combustion of pentene (C5H10) in the presence of oxygen gas will produce carbon dioxide and water vapor according to the chemical equation: 2 C5H10 + 15 02-10 CO₂ + 10 H₂O. How many grams of water will be produced if 248 g of pentene is burned in the presence of 319 g of oxygen gas?

The combustion of pentene (C5H10) in the presence of oxygen gas will produce carbon dioxide and water vapor according
to the chemical equation 2 C5H10+ 15 02-10 CO₂+ 10 H₂0
How many grams of water will be produced if 248 g of pentene is burned in the presence of 319 g of oxygen gas?
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Transcribed Image Text:The combustion of pentene (C5H10) in the presence of oxygen gas will produce carbon dioxide and water vapor according to the chemical equation 2 C5H10+ 15 02-10 CO₂+ 10 H₂0 How many grams of water will be produced if 248 g of pentene is burned in the presence of 319 g of oxygen gas? SAVE ATOWEL
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