The combustion of heptane, C,H16, occurs via the reaction C;H16(g) + 1102(g)→7CO2(g) + 8H20(g) with heat of formation values given by the following table: AH (kJ/mol) Substance CH16 (g) -187.9 CO2(g) -393.5 H20(g) -241.8 Calculate the enthalpy for the combustion of 1 mole of heptane. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) ΔΗ Value Units Submit

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### Understanding Standard Heat of Formation and Reaction Enthalpy

The standard heat of formation, \( \Delta H_f^\circ \), is defined as the enthalpy change for the formation of one mole of a substance from its constituent elements in their standard states. By definition, elements in their standard states have \( \Delta H_f^\circ = 0 \). These formation values are crucial for calculating the enthalpy change of any reaction.

#### Calculation Example

Consider the following reaction:

\[ 2 \text{NO} (g) + \text{O}_2 (g) \rightarrow 2 \text{NO}_2 (g) \]

Using the heat of formation values from the table below:

| Substance | \( \Delta H_f^\circ \) (kJ/mol) |
|-----------|--------------------------------|
| NO (g)    | 90.2                           |
| O2 (g)    | 0                              |
| NO2 (g)   | 33.2                           |

The standard heat of reaction (\( \Delta H_{rxn}^\circ \)) for the overall reaction is calculated as follows:

\[ \Delta H_{rxn}^\circ = \left( \sum \Delta H_f^\circ \text{(products)} \right) - \left( \sum \Delta H_f^\circ \text{(reactants)} \right) \]

\[ \Delta H_{rxn}^\circ = [2(33.2)] - [2(90.2) + 0] \]

\[ \Delta H_{rxn}^\circ = 66.4 - 180.4 \]

\[ \Delta H_{rxn}^\circ = -114 \text{ kJ} \]

### Practice Problem

**Part B: Combustion of Heptane**

The combustion of heptane (\( \text{C}_7\text{H}_{16} \)) is described by the following reaction:

\[ \text{C}_7\text{H}_{16} (g) + 11 \text{O}_2 (g) \rightarrow 7 \text{CO}_2 (g) + 8 \text{H}_2\text{O} (g) \]

Given the heat of formation values from the table below:

| Substance      | \( \Delta H_f^\circ \) (kJ/mol
Transcribed Image Text:### Understanding Standard Heat of Formation and Reaction Enthalpy The standard heat of formation, \( \Delta H_f^\circ \), is defined as the enthalpy change for the formation of one mole of a substance from its constituent elements in their standard states. By definition, elements in their standard states have \( \Delta H_f^\circ = 0 \). These formation values are crucial for calculating the enthalpy change of any reaction. #### Calculation Example Consider the following reaction: \[ 2 \text{NO} (g) + \text{O}_2 (g) \rightarrow 2 \text{NO}_2 (g) \] Using the heat of formation values from the table below: | Substance | \( \Delta H_f^\circ \) (kJ/mol) | |-----------|--------------------------------| | NO (g) | 90.2 | | O2 (g) | 0 | | NO2 (g) | 33.2 | The standard heat of reaction (\( \Delta H_{rxn}^\circ \)) for the overall reaction is calculated as follows: \[ \Delta H_{rxn}^\circ = \left( \sum \Delta H_f^\circ \text{(products)} \right) - \left( \sum \Delta H_f^\circ \text{(reactants)} \right) \] \[ \Delta H_{rxn}^\circ = [2(33.2)] - [2(90.2) + 0] \] \[ \Delta H_{rxn}^\circ = 66.4 - 180.4 \] \[ \Delta H_{rxn}^\circ = -114 \text{ kJ} \] ### Practice Problem **Part B: Combustion of Heptane** The combustion of heptane (\( \text{C}_7\text{H}_{16} \)) is described by the following reaction: \[ \text{C}_7\text{H}_{16} (g) + 11 \text{O}_2 (g) \rightarrow 7 \text{CO}_2 (g) + 8 \text{H}_2\text{O} (g) \] Given the heat of formation values from the table below: | Substance | \( \Delta H_f^\circ \) (kJ/mol
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