The combustion of heptane, C,H16, occurs via the reaction C;H16(g) + 1102(g)→7CO2(g) + 8H20(g) with heat of formation values given by the following table: AH (kJ/mol) Substance CH16 (g) -187.9 CO2(g) -393.5 H20(g) -241.8 Calculate the enthalpy for the combustion of 1 mole of heptane. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) ΔΗ Value Units Submit
The combustion of heptane, C,H16, occurs via the reaction C;H16(g) + 1102(g)→7CO2(g) + 8H20(g) with heat of formation values given by the following table: AH (kJ/mol) Substance CH16 (g) -187.9 CO2(g) -393.5 H20(g) -241.8 Calculate the enthalpy for the combustion of 1 mole of heptane. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) ΔΗ Value Units Submit
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding Standard Heat of Formation and Reaction Enthalpy
The standard heat of formation, \( \Delta H_f^\circ \), is defined as the enthalpy change for the formation of one mole of a substance from its constituent elements in their standard states. By definition, elements in their standard states have \( \Delta H_f^\circ = 0 \). These formation values are crucial for calculating the enthalpy change of any reaction.
#### Calculation Example
Consider the following reaction:
\[ 2 \text{NO} (g) + \text{O}_2 (g) \rightarrow 2 \text{NO}_2 (g) \]
Using the heat of formation values from the table below:
| Substance | \( \Delta H_f^\circ \) (kJ/mol) |
|-----------|--------------------------------|
| NO (g) | 90.2 |
| O2 (g) | 0 |
| NO2 (g) | 33.2 |
The standard heat of reaction (\( \Delta H_{rxn}^\circ \)) for the overall reaction is calculated as follows:
\[ \Delta H_{rxn}^\circ = \left( \sum \Delta H_f^\circ \text{(products)} \right) - \left( \sum \Delta H_f^\circ \text{(reactants)} \right) \]
\[ \Delta H_{rxn}^\circ = [2(33.2)] - [2(90.2) + 0] \]
\[ \Delta H_{rxn}^\circ = 66.4 - 180.4 \]
\[ \Delta H_{rxn}^\circ = -114 \text{ kJ} \]
### Practice Problem
**Part B: Combustion of Heptane**
The combustion of heptane (\( \text{C}_7\text{H}_{16} \)) is described by the following reaction:
\[ \text{C}_7\text{H}_{16} (g) + 11 \text{O}_2 (g) \rightarrow 7 \text{CO}_2 (g) + 8 \text{H}_2\text{O} (g) \]
Given the heat of formation values from the table below:
| Substance | \( \Delta H_f^\circ \) (kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24ca723d-2dd5-46d5-9d14-7e20868efa99%2F71250fd8-ae52-4c00-ad24-bfa5c8c6d572%2F2cqjp2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Standard Heat of Formation and Reaction Enthalpy
The standard heat of formation, \( \Delta H_f^\circ \), is defined as the enthalpy change for the formation of one mole of a substance from its constituent elements in their standard states. By definition, elements in their standard states have \( \Delta H_f^\circ = 0 \). These formation values are crucial for calculating the enthalpy change of any reaction.
#### Calculation Example
Consider the following reaction:
\[ 2 \text{NO} (g) + \text{O}_2 (g) \rightarrow 2 \text{NO}_2 (g) \]
Using the heat of formation values from the table below:
| Substance | \( \Delta H_f^\circ \) (kJ/mol) |
|-----------|--------------------------------|
| NO (g) | 90.2 |
| O2 (g) | 0 |
| NO2 (g) | 33.2 |
The standard heat of reaction (\( \Delta H_{rxn}^\circ \)) for the overall reaction is calculated as follows:
\[ \Delta H_{rxn}^\circ = \left( \sum \Delta H_f^\circ \text{(products)} \right) - \left( \sum \Delta H_f^\circ \text{(reactants)} \right) \]
\[ \Delta H_{rxn}^\circ = [2(33.2)] - [2(90.2) + 0] \]
\[ \Delta H_{rxn}^\circ = 66.4 - 180.4 \]
\[ \Delta H_{rxn}^\circ = -114 \text{ kJ} \]
### Practice Problem
**Part B: Combustion of Heptane**
The combustion of heptane (\( \text{C}_7\text{H}_{16} \)) is described by the following reaction:
\[ \text{C}_7\text{H}_{16} (g) + 11 \text{O}_2 (g) \rightarrow 7 \text{CO}_2 (g) + 8 \text{H}_2\text{O} (g) \]
Given the heat of formation values from the table below:
| Substance | \( \Delta H_f^\circ \) (kJ/mol
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