The combustion analysis of 0.246 g of organic compound containing only C,H&N gives 0.656 g CO2, 0.134 g H20, and 1.86 x 103 mol N2 gas. What would be the empirical formula of this organic compound? O C3H3N2 CAHẠN C2H2N2 C2H2N C3H3N

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**Combustion Analysis Problem - Organic Compound**

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**Problem Statement:**

The combustion analysis of 0.246 g of an organic compound containing only C, H, & N gives 0.656 g of CO₂, 0.134 g of H₂O, and 1.86 × 10⁻³ mol N₂ gas. What would be the empirical formula of this organic compound?

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**Options:**

- ⃝ C₃H₃N₂
- ⃝ C₄H₄N
- ⃝ C₂H₂N₂
- ⃝ C₂H₂N
- ⃝ C₃H₃N

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**Explanation of the Combustion Analysis Diagram:**

This problem is a combustion analysis question where a sample of an organic compound is burned, and the products of the combustion are measured. By determining the amounts of CO₂, H₂O, and N₂ gas produced, we can infer the quantities of C, H, and N in the original compound and derive its empirical formula.

1. **CO₂ Production**: The mass of CO₂ produced can be used to find the amount of carbon (C) in the original compound.
   - Given: 0.656 g CO₂
   - Calculation: Use the molar mass of CO₂ to find the moles of C.

2. **H₂O Production**: The mass of H₂O produced can be used to find the amount of hydrogen (H) in the original compound.
   - Given: 0.134 g H₂O
   - Calculation: Use the molar mass of H₂O to find the moles of H.

3. **N₂ Production**: The moles of N₂ produced is directly given and can be used to find the amount of nitrogen (N) in the original compound.
   - Given: 1.86 × 10⁻³ mol N₂
   - Calculation: Each mole of N₂ represents 2 moles of N atoms.

From these quantities, we can determine the moles of each element in the original compound, establish a ratio, and thus derive the empirical formula.

If you found this educational content helpful, be sure to explore more chemistry problems and analysis on our website to strengthen your understanding!
Transcribed Image Text:**Combustion Analysis Problem - Organic Compound** --- **Problem Statement:** The combustion analysis of 0.246 g of an organic compound containing only C, H, & N gives 0.656 g of CO₂, 0.134 g of H₂O, and 1.86 × 10⁻³ mol N₂ gas. What would be the empirical formula of this organic compound? --- **Options:** - ⃝ C₃H₃N₂ - ⃝ C₄H₄N - ⃝ C₂H₂N₂ - ⃝ C₂H₂N - ⃝ C₃H₃N --- **Explanation of the Combustion Analysis Diagram:** This problem is a combustion analysis question where a sample of an organic compound is burned, and the products of the combustion are measured. By determining the amounts of CO₂, H₂O, and N₂ gas produced, we can infer the quantities of C, H, and N in the original compound and derive its empirical formula. 1. **CO₂ Production**: The mass of CO₂ produced can be used to find the amount of carbon (C) in the original compound. - Given: 0.656 g CO₂ - Calculation: Use the molar mass of CO₂ to find the moles of C. 2. **H₂O Production**: The mass of H₂O produced can be used to find the amount of hydrogen (H) in the original compound. - Given: 0.134 g H₂O - Calculation: Use the molar mass of H₂O to find the moles of H. 3. **N₂ Production**: The moles of N₂ produced is directly given and can be used to find the amount of nitrogen (N) in the original compound. - Given: 1.86 × 10⁻³ mol N₂ - Calculation: Each mole of N₂ represents 2 moles of N atoms. From these quantities, we can determine the moles of each element in the original compound, establish a ratio, and thus derive the empirical formula. If you found this educational content helpful, be sure to explore more chemistry problems and analysis on our website to strengthen your understanding!
### Precipitation of Cd²⁺ Ions

To precipitate Cd²⁺ from solution one could add:

- ○ HNO₃(aq)
- ○ KI(aq)
- ○ H₂S(aq)
- ○ NaCl(aq)
- ○ HCl(aq)

The diagram above lists several aqueous solutions that can be considered when attempting to precipitate cadmium ions (Cd²⁺) from an aqueous solution. Selecting the correct reagent is essential for achieving successful precipitation in a chemical reaction. By understanding the solubility rules and the possible reactions each reagent can partake in, you can determine the optimal choice to form an insoluble compound, causing Cd²⁺ to precipitate.
Transcribed Image Text:### Precipitation of Cd²⁺ Ions To precipitate Cd²⁺ from solution one could add: - ○ HNO₃(aq) - ○ KI(aq) - ○ H₂S(aq) - ○ NaCl(aq) - ○ HCl(aq) The diagram above lists several aqueous solutions that can be considered when attempting to precipitate cadmium ions (Cd²⁺) from an aqueous solution. Selecting the correct reagent is essential for achieving successful precipitation in a chemical reaction. By understanding the solubility rules and the possible reactions each reagent can partake in, you can determine the optimal choice to form an insoluble compound, causing Cd²⁺ to precipitate.
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