The color of some beans is controlled by three different genes, A, B, and C, making bean color a polygenic treat. If we start with parents that are heterozygous for each gene, then for each individual genotype, probability can be deduced using a simple Punnett Square. Below are Punnett Squares for each individual gene. А a B b C A AA Aa BB Bb C CC Сс a Aa aa Ва bb Сс CC AA = 25% ВВ 3 25% СС 3 25% Which rule for calculating probability (And Rule or Or Rule) would be used to determine the probability of a bean with the genotype AABBCC? Therefore, to calculate the probability of a bean being AA, BB, and CC, the individual probabilities would need to be (Note: this is not asking for a number - it's asking you what you need to do mathematically with the individual probabilities to calculate a bean being AA, BB, CC.) The probability of a bean being AABBCC is • Report your answer as a percent and round to two decimal places. B.

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