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The color of some beans is controlled by three different genes, A, B, and C, making bean color a polygenic treat. If we start with parents that are heterozygous for each gene, then for each individual genotype, probability can be deduced using a simple Punnett Square. Below are Punnett Squares for each individual gene. b B Cc Bb AA Aa BB CC bb Aa Ba Cc a aa CC CC = 25% BB = 25% AA = 25% Which rule for calculating probability (And Rule or Or Rule) would be used to determine the probability of a bean with the genotype AABBCC? Product rule Therefore, to calculate the probability of a bean being AA, BB, and CC, the individual probabilities would need to be multiplied (Note: this is not asking for a number - it's asking you what you need to do mathematically with the individual probabilities to calculate a bean being AA, BB, CC.) The probability of a bean being AABBCC is 1.56 • Report your answer as a percent and round to two decimal places. Given a parent plant with the genotype AaBbCc is mated with a plant with genotype AaBbCc, what is the probability of an F1 offspring with the genotype AABBCC? Express your answer as a percent, but do not include the percent symbol (%). E.g an answer of 0.3333 would be reported as 33.33, not as 1/3 or 0.333 or 33.33% Do not round your answer. 3.125

The color of some beans is controlled by three different genes, A, B, and C, making bean color a polygenic treat. If we start with parents that are heterozygous for each gene, then for each individual genotype, probability can be deduced using a simple Punnett Square. Below are Punnett Squares for each individual gene. b B Cc Bb AA Aa BB CC bb Aa Ba Cc a aa CC CC = 25% BB = 25% AA = 25% Which rule for calculating probability (And Rule or Or Rule) would be used to determine the probability of a bean with the genotype AABBCC? Product rule Therefore, to calculate the probability of a bean being AA, BB, and CC, the individual probabilities would need to be multiplied (Note: this is not asking for a number - it's asking you what you need to do mathematically with the individual probabilities to calculate a bean being AA, BB, CC.) The probability of a bean being AABBCC is 1.56 • Report your answer as a percent and round to two decimal places. Given a parent plant with the genotype AaBbCc is mated with a plant with genotype AaBbCc, what is the probability of an F1 offspring with the genotype AABBCC? Express your answer as a percent, but do not include the percent symbol (%). E.g an answer of 0.3333 would be reported as 33.33, not as 1/3 or 0.333 or 33.33% Do not round your answer. 3.125

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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The color of some beans is controlled by three different genes, A, B, and C, making bean color a polygenic treat. If we start with parents that are heterozygous for each gene, then for each individual genotype, probability can be deduced using a simple Punnett Square. Below are Punnett Squares for each individual gene. b B Cc Bb AA Aa BB CC bb Aa Ba Cc a aa CC CC = 25% BB = 25% AA = 25% Which rule for calculating probability (And Rule or Or Rule) would be used to determine the probability of a bean with the genotype AABBCC? Product rule Therefore, to calculate the probability of a bean being AA, BB, and CC, the individual probabilities would need to be multiplied (Note: this is not asking for a number - it's asking you what you need to do mathematically with the individual probabilities to calculate a bean being AA, BB, CC.) The probability of a bean being AABBCC is 1.56 • Report your answer as a percent and round to two decimal places. Given a parent plant with the genotype AaBbCc is mated with a plant with genotype AaBbCc, what is the probability of an F1 offspring with the genotype AABBCC? Express your answer as a percent, but do not include the percent symbol (%). E.g an answer of 0.3333 would be reported as 33.33, not as 1/3 or 0.333 or 33.33% Do not round your answer. 3.125
Transcribed Image Text:The color of some beans is controlled by three different genes, A, B, and C, making bean color a polygenic treat. If we start with parents that are heterozygous for each gene, then for each individual genotype, probability can be deduced using a simple Punnett Square. Below are Punnett Squares for each individual gene. b B Cc Bb AA Aa BB CC bb Aa Ba Cc a aa CC CC = 25% BB = 25% AA = 25% Which rule for calculating probability (And Rule or Or Rule) would be used to determine the probability of a bean with the genotype AABBCC? Product rule Therefore, to calculate the probability of a bean being AA, BB, and CC, the individual probabilities would need to be multiplied (Note: this is not asking for a number - it's asking you what you need to do mathematically with the individual probabilities to calculate a bean being AA, BB, CC.) The probability of a bean being AABBCC is 1.56 • Report your answer as a percent and round to two decimal places. Given a parent plant with the genotype AaBbCc is mated with a plant with genotype AaBbCc, what is the probability of an F1 offspring with the genotype AABBCC? Express your answer as a percent, but do not include the percent symbol (%). E.g an answer of 0.3333 would be reported as 33.33, not as 1/3 or 0.333 or 33.33% Do not round your answer. 3.125
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