Variant Function 0 1 2 3 4 5 6 7 8 9 10 |_y=4*x²-3*x²+6*x-7 y = 0.25*x +4sin(x)-3 y = sin(2x)*exp(0.05x+6)+3 y=-2*x³-4*x+9*x + In(x+6) y = 0.05 * x²-4*x²+5*x+4 y = 1.5*x* sin(2x-3) y = 5*exp(-0.05x)*sin(2x)+1 y = 5* sin(2x) + 7*ln(x+6)-12 y = sin(3x+2)*exp(0.03x+1) y=-3*x³-2*x²+6*x + ln(x+6) y = 0.05*x³+6sin(3x)+4 Range From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 From 5 to 5 From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 From 5 to 5 From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 Step 0.5 1 0.5 1 0.5 1 0.5 1 0.5 1 0.5 Specified value of y 20 2 99 -15 5 24 0 6 -1 4 -2
Variant Function 0 1 2 3 4 5 6 7 8 9 10 |_y=4*x²-3*x²+6*x-7 y = 0.25*x +4sin(x)-3 y = sin(2x)*exp(0.05x+6)+3 y=-2*x³-4*x+9*x + In(x+6) y = 0.05 * x²-4*x²+5*x+4 y = 1.5*x* sin(2x-3) y = 5*exp(-0.05x)*sin(2x)+1 y = 5* sin(2x) + 7*ln(x+6)-12 y = sin(3x+2)*exp(0.03x+1) y=-3*x³-2*x²+6*x + ln(x+6) y = 0.05*x³+6sin(3x)+4 Range From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 From 5 to 5 From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 From 5 to 5 From -2.5 to 2.5 From -5 to 5 From -2.5 to 2.5 Step 0.5 1 0.5 1 0.5 1 0.5 1 0.5 1 0.5 Specified value of y 20 2 99 -15 5 24 0 6 -1 4 -2
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
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in C++ use function variant 10 from the functions table to make the same output in the example picture;
![Variant Function
0
1
2
3
4
5
6
7
8
9
10
|_y=4*x*-3*x²+6*x-7
y = 0.25*x +4sin(x)-3
y = sin(2x)*exp(0.05x+6)+3
y = -2*x³-4*x²+9*x + ln(x+6)
y = 0.05 *x²-4*x²+5*x+4
y = 1.5*x* sin(2x-3)
y = 5*exp(-0.05x)* sin(2x)+1
y = 5* sin(2x) + 7*ln(x+6)-12
y = sin(3x+2)*exp(0.03x+1)
y=-3*x²-2*x²+6*x+ln(x+6)
y = 0.05*x³+6sin(3x)+4
Range
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
| From -5 to 5
From -2.5 to 2.5
Step
0.5
1
0.5
1
0.5
1
0.5
1
0.5
1
0.5
Specified value of
y
20
2
99
-15
5
24
0
6
-1
4
-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2038891b-1da1-4fac-91c5-dd8fac246fa2%2F5ad77f9e-76f9-4166-9b1d-5a36df210eb2%2Fz4i8bei_processed.png&w=3840&q=75)
Transcribed Image Text:Variant Function
0
1
2
3
4
5
6
7
8
9
10
|_y=4*x*-3*x²+6*x-7
y = 0.25*x +4sin(x)-3
y = sin(2x)*exp(0.05x+6)+3
y = -2*x³-4*x²+9*x + ln(x+6)
y = 0.05 *x²-4*x²+5*x+4
y = 1.5*x* sin(2x-3)
y = 5*exp(-0.05x)* sin(2x)+1
y = 5* sin(2x) + 7*ln(x+6)-12
y = sin(3x+2)*exp(0.03x+1)
y=-3*x²-2*x²+6*x+ln(x+6)
y = 0.05*x³+6sin(3x)+4
Range
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
From 5 to 5
From -2.5 to 2.5
| From -5 to 5
From -2.5 to 2.5
Step
0.5
1
0.5
1
0.5
1
0.5
1
0.5
1
0.5
Specified value of
y
20
2
99
-15
5
24
0
6
-1
4
-2
![1. This program will calculate value of the function for range of x and steps given in your variant. Use
vectors x and y to store corresponding values of x and y. Make a C++ function my_func() to calculate
value of y for the given x. Use tabulation '\t' to make an output that looks like a table. The output must be
similar to following:
My name is Alina Latipova. My variant is 0.
Function is y = 4*x^4-3*x^2+6*x-7
-2.5 -2
116.5 34
-1.5 -1 -0.5 0
-1.5 -11 -9.5 -6
0.5 1
-3.5 1
1.5 2
2.5
16.5 58 146.5
X
у
2. The program also calculates max and min values for the given range. Use max_element()) and
min_element() functions using algorithm header. The output must be similar to following:
Max value of function y for the given range is 146.5
Min value is -9.5
3. The program must choose value of x from the given range which gives the value of function y closest
to the specified value of y. The output must be similar to following:
Value of function y specified 20
Closest value of function y is 16.5 for x = 1.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2038891b-1da1-4fac-91c5-dd8fac246fa2%2F5ad77f9e-76f9-4166-9b1d-5a36df210eb2%2F0e88jt_processed.png&w=3840&q=75)
Transcribed Image Text:1. This program will calculate value of the function for range of x and steps given in your variant. Use
vectors x and y to store corresponding values of x and y. Make a C++ function my_func() to calculate
value of y for the given x. Use tabulation '\t' to make an output that looks like a table. The output must be
similar to following:
My name is Alina Latipova. My variant is 0.
Function is y = 4*x^4-3*x^2+6*x-7
-2.5 -2
116.5 34
-1.5 -1 -0.5 0
-1.5 -11 -9.5 -6
0.5 1
-3.5 1
1.5 2
2.5
16.5 58 146.5
X
у
2. The program also calculates max and min values for the given range. Use max_element()) and
min_element() functions using algorithm header. The output must be similar to following:
Max value of function y for the given range is 146.5
Min value is -9.5
3. The program must choose value of x from the given range which gives the value of function y closest
to the specified value of y. The output must be similar to following:
Value of function y specified 20
Closest value of function y is 16.5 for x = 1.5
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