The CLARITY_SER table contains information about providers. Which of the following queries successfully creates a temp table that stores the names of providers who are pharmacists (PHARMACIST_YN = 'Y')? ONE OF THE FOLLOWING (2 PTS) A. SELECT PROV_NAME INTO #Pharm FROM CLARITY_SER WHERE PHARMACIST_YN = 'Y' B. SELECT PROV_NAME FROM CLARITY_SER WHERE PHARMACIST YN = 'Y' INTO #Pharm C. SELECT PROV_NAME FROM CLARITY_SER INTO #Pharm WHERE PHARMACIST_YN = 'Y' D. SELECT INTO #Pharm FROM CLARITY_SER.PROV_NAME WHERE PHARMACIST_YN = 'Y'

The CLARITY_SER table contains information about providers. Which of the following queries successfully creates a temp table that stores the names of providers who are pharmacists (PHARMACIST_YN = 'Y')? ONE OF THE FOLLOWING (2 PTS) A. SELECT PROV_NAME INTO #Pharm FROM CLARITY_SER WHERE PHARMACIST_YN = 'Y' B. SELECT PROV_NAME FROM CLARITY_SER WHERE PHARMACIST YN = 'Y' INTO #Pharm C. SELECT PROV_NAME FROM CLARITY_SER INTO #Pharm WHERE PHARMACIST_YN = 'Y' D. SELECT INTO #Pharm FROM CLARITY_SER.PROV_NAME WHERE PHARMACIST_YN = 'Y'

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

To add new customer to the customer table, the right query is: insert into customer new (4, 'sa 'beirut', lebanon') insert new customer (4, 'sami', 'beirut', lebanon') insert new customer values (4, 'sami', 'beirut', lebanon') insert into customer values (4, 'sami', 'beirut', lehanon')
Which query will use the given columns from the PRODUCT table to determine the total value of inventory held on hand? P_QOH = quantity on hand P_PRICE = price a. SELECT P_DESCRIPT, P_QOH, P_PRICE, P_QOH/P_PRICE FROM PRODUCT; b. SELECT P_DESCRIPT, P_QOH, P_PRICE, P_QOH=P_PRICE FROM PRODUCT; c. SELECT P_DESCRIPT, P_QOH, P_PRICE, P_QOH-P_PRICE FROM PRODUCT; d. SELECT P_DESCRIPT, P_QOH, P_PRICE, P_QOH*P_PRICE FROM PRODUCT;
Which type of join is demonasted by the folloing query? Select from make. model where make modelID to mode ID a) Non-Equlion b) Self Join c) Cross Join d) Equijoin
In Structure Query Information Select all columns from the jobs table using an asterisk.2. Select only job title, min salary, and max salary columns from the jobs table.3. Select all columns from the d_partners table by writing out all of the columns inthe select statement.4. Using the d_partners table, display the id, and then concatenate the first_nameand last_name together with a space in between the two columns. Give theconcatenated column an alias of NAME. Be sure to use the optional ASkeyword.5. Using the job_grades table, show the grade level, and then subtract thelowest_sal from the highest_sal to show the amount of variance there is for eachgrade level. Give the calculated column an alias of Salary_Variance. Do notuse the optional AS keyword.6. Using the employees table, show an unduplicated list of department_id’s.7. Change the SELECT statement you built for question 4, adding a single columncalled Partner_Information that concatenates the partner’s…
Write a SQL query to find the customer# of those customers that purchased at least once in July 2020 but NOT in August 2020. In addition to the customer#, show the ISBN and title of the book(s) they purchased in July 2020. You may use only one query. No creating any temporary tables or subqueries. You may use only joins. SUBMIT a second solution in addition to your Level 1.
Lab #9 – Joining Data From Multiple Tables List the order number and order date for every order that was placed by Mary Nelson and that contains an order line for an iron. Use an INTERSECT operator. Lab #10 – Sub Queries Find the sales rep number, last name, and first name for every sales rep who represents at least one customer with a credit limit of $2000. List the order number and order date for every order that was placed by Mary Nelson and that contains an order line for an iron. Down below are the tables ORDER_LINE ORLN_ORDER_NUMBER ORLN_PART_NUMBER ORLN_NUMBER_ORDERED ORLN_QUOTED_PRICE ORDER_TABLE ORDR_ORDER_NUMBER ORDR_ORDER_DATE ORDR_CUSTOMER_NUMBER CUSTOMER CUST_NUMBER CUST_LAST CUST_FIRST CUST_STREET CUST_CITY CUST_STATE CUST_ZIP_CODE CUST_BALANCE CUST_CREDIT_LIMIT CUST_SALES_REP_NUM PART PART_NUMBER PART_DESCRIPTION UNITS_ON_HAND…
Write the SQL code that will produce the results shown as below. Write the SQL code to calculate the ASSIGN_CHARGE values in the ASSIGNMENT table. Note that ASSIGN_CHARGE is a derived attribute that is calculated by multiplying ASSIGN_CHG_HR by ASSIGN_HOURS. Write the SQL code that will yield the total number of hours worked for each employee and the total charges stemming from those hours worked. The result is shown as below.
query no 2 is select avg(CustBal) from Customer where CusState='WA' GROUP BY city. Here aggregate function avg is used to calculate average of customer balance.next where statement is used to filter the customer who live in Washington state and at last group by clause is used to show the balance city wise.
Question 14 List the three mistakes in the following SQL code: SELECT tblCustomer FIELD Customer#, CustomerFirstName, CustomerLastName CRITERIA Customer#=100;
Lab #9 – Joining Data From Multiple Tables List the order number and order date for every order that was placed by Mary Nelson and that contains an order line for an iron. Use an INTERSECT operator. Lab #10 – Sub Queries Find the sales rep number, last name, and first name for every sales rep who represents at least one customer with a credit limit of $2000. List the order number and order date for every order that was placed by Mary Nelson and that contains an order line for an iron. Repeat the exercise from the prior step using the ANY operator in the query instead of the ALL operator.
Which one of the following SQL select statements will display a list of all vendors that do not yet have names entered in the vendor table? Question 8 options: 1) select vend_code, vend_name from vendor where vend_name IS NULL; 2) select vend_code, vend_name from vendor where vend_name IS NOT NULL; 3) select vend_code, vend_name from vendor where vend_name = NULL; 4) select vend_code, vend_name from vendor where vend_name = NOT NULL;