The claim for a marketing campaign is that 0.59 of clients respond, and you want to prove it is more. Your survey of 205 clientsshowed 149 respond. Test the hypothesis at a 1% level of significance.Level of difficulty = 2 of 3Please format to 2 decimal places.Number of Tails:Test Statistic:Critical z in the Decision Rule:o Both + and -Reject or Not:

Let p be the population proportion X be the number of response n=sample size X=149, n=205, level…

Answered: The claim for a marketing campaign is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Student loan debt is the only form of consumer debt that has grown since the peak of consumer debt in 2008. The average student loan of somebody younger than 30 is
The government of a certain country says that the literacy rate (the proportion of people who are literate) in the country is 73%. A nongovernmental organization believes that the rate is lower than that. To test their belief at the 1% significance level, the organization studies a random sample of 420 people and finds that 283 of them are literate. Ho: p=0.73 Ha: P< 0.73 Find the P-value. Round your answer to 3 decimal places.
You need to use Stata to look up the dataset and its variables. Use Stata Companion Textbook. (Dataset: NES. Variables: spend8, [pw=nesw].) The NES dataset contains spend8, which records the number of government policy areas where respondents think spending should be increased. Scores range from 0 (the respondent does not want to increase spending on any of the policies) to 8 (the respondent wants to increase spending on all eight policies). The NES, of course, polls a random sample of U.S. adults. In this exercise you will analyze spend8 using the mean and lincom commands. You then will draw inferences about the population mean. (Remember to specify nesw as the probability weight.) The spend8 variable has a sample mean of ______. Make sure you use [pw=nesw] so your results are nationally representative. There is a probability of .95 that spend8’s true population mean falls between a score of ______ at the low end and a score of ______ at the high end. A student researcher…
The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.25 and the sample statistics include n=1150 subjects with 265 saying that they smoked a cigarette in the past week. Find the value of the test statistic.
Need help with # 13
You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats.You sample 190 men, and 71 own cats.You sample 130 women, and 114 own cats.Find the test statistic, rounded to two decimal places
According to a report on consumer fraud and identity theft, 22% of all complaints for a year were for identity theft. In that year, Wisconsin had 787 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Wisconsin had a higher proportion of identity theft than 22%? Test at the 1% level. State the hypotheses. Ho: p? v Ha: p|? v Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. Z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .01, reject Họ. O Since the p-value is greater than .01, reject Ho. O Since the p-value is less than .01, fail to reject Ho. O Since the p-value is greater than .01, fail to reject Ho. Interpret the results. O At the 1% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Wisconsin is not equal to…
Q3.3 Normal, but why? A meal package for use at the space station is to be prepared by combining three separate components: protein, fruit/vegetable, and grains. Each of the components is to be randomly selected. Summary values for the caloric content for each of the components are given in the table. Component Protein (P) Fruit/vegetable (F) Grain (G) Mean (calories) 120 55 84 Stdv (calories) 6.4 Save Answer 1.0 3.6 Assume that the distributions of caloric content for each of the components are approximately normally distributed. Since the meal package consists of protein, fruit/vegetable, and grains, the total caloric content of a meal package is the random variable T, where T = P + F + G. Briefly explain why it is appropriate to say that T is approximately normally distributed. Q3.4 Probability Less than 275 Calories On your own piece of paper find the approximate probability that a randomly selected meal package will have less than 269 calories? (Draw an appropriate diagram, find a…
A teacher claims that over 9% of maths students are married. In the survey at the beginning of semester, 45 students answered the question about their marital status. 9 of them said they were married. Calculate the test statistic Z? Round answer to 2 decimals
ou are doing a problem where you have a negative z-score, and you have to look up the proportion of the shaded area in the tail beyond that z-score; in other words, you are shading to the left from your z-score, and looking for the proportion that you shaded. Four “proportions” are given below. Which one is the ONLY one that could potentially be the number you are looking for? (Hint: Think about what you know about proportions: What kind of number are they? And what things can they represent?) Group of answer choices p = 0.3800 p = -0.1500 p = 1.1500 p = 0.5635
Please answer all parts. One question, This is not graded. it is practice
A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?

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