Need help with part 1 Calculate the orbital velocity (in km/s) of a ring particlethat orbits 86000 km from the center of Saturn.What is the Roche limit (in km) for Saturn?Find the moon in the table below that is closest to thisradius. What is its orbital velocity (in km/s)?Selection of Principal Satellites of the Solar SystemDistance fromPrimarySatelliteRadius (km)Primary (103 km)JupiterAmal thea135 x 100 x 78182lo1,820422Europa1,560671Ganymede2,6301,071Callisto2,4101,884Himalia~8511,470SaturnJanus110 x 80 x 100151.5Mimas196185.5Enceladus260238.0Tethys530294.7Dione560377Rhea765527Titan2,5751,222Нурerion205 x 130 x 1101,484lapetus7203,562Phoebe10512,930Part 1 of 3The circular velocity equation can be used todetermine the orbital velocity of a ring particle.GMV = VCalculate the orbital velocity of a ring particle thatorbits 86000 km from the center of Saturn.GMV =V =km/s

Orbital velocity is the speed required for an object such as a satellite to maintain a balance between the force of gravity (gravitational pull) acting on the satellite and the inertial motion (tendency to keep moving away) of the satellite. It is required for satellite launches to be successful because it allows the satellite to keep orbiting the planet and provide valuable data in a consistent manner. The orbital velocity formula is: ν = GMr where, G is the gravitational constant, M is the mass of the planet (Saturn) at its center, and r is the orbital radius of the ring particle. This is the distance between the center of the planet Saturn and the ring particle. Values: G = 6.673 x 10-11 m3.s-2.kg-1 MSaturn = 5.683 x 1026 kg r = 86000 km The gravitation constant is in units of meters so we must convert the orbital radius into meters. 1 km = 1000 m 86000 km = 86000000 m Now, the orbital velocity in the unit of meters per second can be calculated as: ν = 6.673×10-11 m3s2.kg × 5.683×1026 kg86000000 mν = 20999.075 msv = 20.999075 kms