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The circuit shown in Fig. 3.64 includes a device known as an op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and "+" inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation-in direct conflict with KCL-is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (Hint: two KVL equations are required, both involving the 5 V source.) 470 2 100 A OP AMP OUT FIGURE 3.64

The circuit shown in Fig. 3.64 includes a device known as an op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and "+" inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation-in direct conflict with KCL-is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (Hint: two KVL equations are required, both involving the 5 V source.) 470 2 100 A OP AMP OUT FIGURE 3.64

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The circuit shown in Fig. 3.64 includes a device known as an op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and "+" inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation-in direct conflict with KCL-is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (Hint: two KVL equations are required, both involving the 5 V source.) 470 A 100 N OP AMP OUT FIGURE 3.64
Transcribed Image Text:The circuit shown in Fig. 3.64 includes a device known as an op amp. This device has two unusual properties in the circuit shown: (1) Vd = 0 V, and (2) no current can flow into either input terminal (marked "-" and "+" inside the symbol), but it can flow through the output terminal (marked "OUT"). This seemingly impossible situation-in direct conflict with KCL-is a result of power leads to the device that are not included in the symbol. Based on this information, calculate Vout. (Hint: two KVL equations are required, both involving the 5 V source.) 470 A 100 N OP AMP OUT FIGURE 3.64
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