The circuit diagram below shows a low pass RC filter circuit, the function of which is to produce a potential difference at the output terminals (v) that resembles the potential difference at the input terminals (vin), but with any high frequency elements (e.g. noise) attenuated. R Vịn C The value of v is governed by the ODE dv RC + v = Vin dt Given that (in SI units) R = 10°, C = 10-7, Vin = sin(t) and v(0)= 0,

Q: eot cosat-sinat-1 f(t)

A: Laplace transferom of divisible by t theorem

Q: 2 F (s) = e-58 s2 + 4

A: Given the given functions are Fs=e-3ss2 Fs=2e-5ss2+4 Apply formula L-1Gse-as=gt-aut-a.

Q: -t cos(3t

A: To solve this problem, we  use the  result of laplace transformation.

Q: Use the transforms in the table below to find the inverse Laplace trans form of the following…

A: By using given table we will find the Laplace inverse transformation.

Q: f(t) = t'g(t)

A: Sol:-We can use the formula: L-1F(s)=-1tddsL-1F(s) where F(s) = L(f(t)) and L-1 denotes the inverse…