The chlorination of methane occurs in a number of steps that results in the formation of chloromethane and hydrogen chloride. The overall reaction is 2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g) Suppose that a chemist combines 257 mL of methane and 599 mL of chlorine at STP in a 2.00 L flask. The flask is then allowed to stand at 298 K. If the reaction reaches 87.2% completion, (a) What is the partial pressure of CH3Cl? (b) What is the partial pressure of HCl? (c) What is the partial pressure of Cl−?
The chlorination of methane occurs in a number of steps that results in the formation of chloromethane and hydrogen chloride. The overall reaction is 2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g) Suppose that a chemist combines 257 mL of methane and 599 mL of chlorine at STP in a 2.00 L flask. The flask is then allowed to stand at 298 K. If the reaction reaches 87.2% completion, (a) What is the partial pressure of CH3Cl? (b) What is the partial pressure of HCl? (c) What is the partial pressure of Cl−?
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The chlorination of methane occurs in a number of steps that results in the formation of chloromethane and hydrogen chloride. The overall reaction is
2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g)
Suppose that a chemist combines 257 mL of methane and 599 mL of chlorine at STP in a 2.00 L flask. The flask is then allowed to stand at 298 K. If the reaction reaches 87.2% completion,
(a) What is the partial pressure of CH3Cl?
(b) What is the partial pressure of HCl?
(c) What is the partial pressure of Cl−?
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Step 1: Interpretation of given data and calculation of given number of moles
VIEWStep 2: Predicting the limiting reagent in the reaction
VIEWStep 3: Number of moles that react upon completion of 87.2% of the reaction
VIEWStep 4: Calculation of respective number of moles using stoichiometry
VIEWStep 5: Calculation of total pressure of the system
VIEWStep 6: Calculation of final partial pressure of the required species
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