The chemical reaction shown was performed and the concentration of HCI was measured over time. Cl₂(g) + CHC1₂(g) →→→ HCI(g) + CC1₂(g) The [HC] after 23 s was 0.049 mol/L. After 146 s, the [HCI] was 0.463 mol/L. Calculate the rate of reaction.

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**Chemical Reaction and Rate of Reaction Calculation**

The chemical reaction shown was performed, and the concentration of HCl was measured over time:

\[ \text{Cl}_2(g) + \text{CHCl}_3(g) \rightarrow \text{HCl}(g) + \text{CCl}_4(g) \]

**Observations:**
- After 23 seconds, the concentration of \[\text{HCl}\] was 0.049 mol/L.
- After 146 seconds, the concentration of \[\text{HCl}\] was 0.463 mol/L.

**Task:**
Calculate the rate of reaction.

**Calculation:**
The rate of reaction can be calculated using the formula:

\[ \text{Rate of reaction} = \frac{\Delta[\text{HCl}]}{\Delta t} \]

Where:
- \(\Delta[\text{HCl}]\) is the change in concentration of HCl.
- \(\Delta t\) is the change in time.

In this problem:
- \(\Delta[\text{HCl}] = 0.463 \, \text{mol/L} - 0.049 \, \text{mol/L} = 0.414 \, \text{mol/L}\)
- \(\Delta t = 146 \, \text{s} - 23 \, \text{s} = 123 \, \text{s}\)

Therefore:
\[ \text{Rate of reaction} = \frac{0.414 \, \text{mol/L}}{123 \, \text{s}} \approx 3.37 \times 10^{-3} \, \text{mol HCl/L/s} \]

In the provided solution, the calculated rate of 2.295 x 10^-3 mol HCl/L/s was marked as incorrect.
Transcribed Image Text:**Chemical Reaction and Rate of Reaction Calculation** The chemical reaction shown was performed, and the concentration of HCl was measured over time: \[ \text{Cl}_2(g) + \text{CHCl}_3(g) \rightarrow \text{HCl}(g) + \text{CCl}_4(g) \] **Observations:** - After 23 seconds, the concentration of \[\text{HCl}\] was 0.049 mol/L. - After 146 seconds, the concentration of \[\text{HCl}\] was 0.463 mol/L. **Task:** Calculate the rate of reaction. **Calculation:** The rate of reaction can be calculated using the formula: \[ \text{Rate of reaction} = \frac{\Delta[\text{HCl}]}{\Delta t} \] Where: - \(\Delta[\text{HCl}]\) is the change in concentration of HCl. - \(\Delta t\) is the change in time. In this problem: - \(\Delta[\text{HCl}] = 0.463 \, \text{mol/L} - 0.049 \, \text{mol/L} = 0.414 \, \text{mol/L}\) - \(\Delta t = 146 \, \text{s} - 23 \, \text{s} = 123 \, \text{s}\) Therefore: \[ \text{Rate of reaction} = \frac{0.414 \, \text{mol/L}}{123 \, \text{s}} \approx 3.37 \times 10^{-3} \, \text{mol HCl/L/s} \] In the provided solution, the calculated rate of 2.295 x 10^-3 mol HCl/L/s was marked as incorrect.
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