The chemical reaction shown was performed and the concentration of HCI was measured over time. Cl₂(g) + CHC1₂(g) →→→ HCI(g) + CC1₂(g) The [HC] after 23 s was 0.049 mol/L. After 146 s, the [HCI] was 0.463 mol/L. Calculate the rate of reaction.
The chemical reaction shown was performed and the concentration of HCI was measured over time. Cl₂(g) + CHC1₂(g) →→→ HCI(g) + CC1₂(g) The [HC] after 23 s was 0.049 mol/L. After 146 s, the [HCI] was 0.463 mol/L. Calculate the rate of reaction.
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![**Chemical Reaction and Rate of Reaction Calculation**
The chemical reaction shown was performed, and the concentration of HCl was measured over time:
\[ \text{Cl}_2(g) + \text{CHCl}_3(g) \rightarrow \text{HCl}(g) + \text{CCl}_4(g) \]
**Observations:**
- After 23 seconds, the concentration of \[\text{HCl}\] was 0.049 mol/L.
- After 146 seconds, the concentration of \[\text{HCl}\] was 0.463 mol/L.
**Task:**
Calculate the rate of reaction.
**Calculation:**
The rate of reaction can be calculated using the formula:
\[ \text{Rate of reaction} = \frac{\Delta[\text{HCl}]}{\Delta t} \]
Where:
- \(\Delta[\text{HCl}]\) is the change in concentration of HCl.
- \(\Delta t\) is the change in time.
In this problem:
- \(\Delta[\text{HCl}] = 0.463 \, \text{mol/L} - 0.049 \, \text{mol/L} = 0.414 \, \text{mol/L}\)
- \(\Delta t = 146 \, \text{s} - 23 \, \text{s} = 123 \, \text{s}\)
Therefore:
\[ \text{Rate of reaction} = \frac{0.414 \, \text{mol/L}}{123 \, \text{s}} \approx 3.37 \times 10^{-3} \, \text{mol HCl/L/s} \]
In the provided solution, the calculated rate of 2.295 x 10^-3 mol HCl/L/s was marked as incorrect.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d79c4c-40ce-427b-b4a0-26ffd9f423cd%2F761a7275-aea2-4f55-b3b8-896b7fde1ffd%2Fdnvnii_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction and Rate of Reaction Calculation**
The chemical reaction shown was performed, and the concentration of HCl was measured over time:
\[ \text{Cl}_2(g) + \text{CHCl}_3(g) \rightarrow \text{HCl}(g) + \text{CCl}_4(g) \]
**Observations:**
- After 23 seconds, the concentration of \[\text{HCl}\] was 0.049 mol/L.
- After 146 seconds, the concentration of \[\text{HCl}\] was 0.463 mol/L.
**Task:**
Calculate the rate of reaction.
**Calculation:**
The rate of reaction can be calculated using the formula:
\[ \text{Rate of reaction} = \frac{\Delta[\text{HCl}]}{\Delta t} \]
Where:
- \(\Delta[\text{HCl}]\) is the change in concentration of HCl.
- \(\Delta t\) is the change in time.
In this problem:
- \(\Delta[\text{HCl}] = 0.463 \, \text{mol/L} - 0.049 \, \text{mol/L} = 0.414 \, \text{mol/L}\)
- \(\Delta t = 146 \, \text{s} - 23 \, \text{s} = 123 \, \text{s}\)
Therefore:
\[ \text{Rate of reaction} = \frac{0.414 \, \text{mol/L}}{123 \, \text{s}} \approx 3.37 \times 10^{-3} \, \text{mol HCl/L/s} \]
In the provided solution, the calculated rate of 2.295 x 10^-3 mol HCl/L/s was marked as incorrect.
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