Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 2.37 µC, x1 = 5.87 cm, y1 = 0.494 cm and 92 = -6.49 µC, x2 = -2.14 cm, y2 = 1.12 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle o charge q3 = 6.63 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units > >

The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 2.37 µC, x1 = 5.87 cm, y1 = 0.494 cm and 92 = -6.49 µC, x2 = -2.14 cm, y2 = 1.12 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle o charge q3 = 6.63 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units > >

icon
Related questions
Question
100%
The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 2.37 µC, x1 = 5.87 cm, y1 = 0.494 cm and 92 = -6.49 µC, x2 = -2.14 cm, y2 = 1.12 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle of charge q3 = 6.63 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units > >
Transcribed Image Text:The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 2.37 µC, x1 = 5.87 cm, y1 = 0.494 cm and 92 = -6.49 µC, x2 = -2.14 cm, y2 = 1.12 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle of charge q3 = 6.63 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units > >
•15 Go The charges and coordinates of two charged particles held fixed in an xy plane are q = +3.0 µC, x1 = 3.5 cm, y = 0.50 cm, and q2 = -4.0 µC, x, = -2.0 cm, y, = 1.5 cm. Find the (a) magni- tude and (b) direction of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third parti- cle of charge q3 = +4.0 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? Your answer is partially correct. The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 3.11 µC, x1 = 5.01 cm, y1 = 0.163 cm and 92 = -3.84 µC, x2 = -2.24 cm, y2 = 1.95 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°]) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle of charge q3 - 4.86 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number 19.3 Units N 15. (a) The distance between qi and q2 is (b) Number -13.8 Units * (degrees) rz =(x, -x,)* +(y, -x) =(-0.020 m–0.035 m)* +(0.015 m–0.005 m)* =0.056 m. The magnitude of the force exerted by q, on q; is (c) Number Units -0.095 m (8.99×10°N-m²/C) (3.0×10 C) (4.0×10ʻC) (0.056 m) F =k =35 N. (d) Number 0.037 Units m (b) The vector Ē, is directed toward gj and makes an angle Owith the +x axis, where 972 СНАРТER 21 1.5 cm-0.5 cm 0= tan - = tan =-10.3°-10°. -2.0 cm-3.5 cm (c) Let the third charge be located at (x3, ya), a distance r from q2. We note that qı, 92, and q3 must be collinear; otherwise, an equilibrium position for any one of them would be impossible to find. Furthermore, we cannot place q3 on the same side of q2 where we also find q1, since in that region both forces (exerted on q2 by q3 and qi) would be in the same direction (since qz is attracted to both of them). Thus, in terms of the angle found in part (a), we have x =x -r coso and y "y2 -r sino(which means y3 > y2 since O is negative). The magnitude of force exerted on q2 by q3 is F=k|q:9, Vr, which must equal that of the force exerted on it by q, (found in part (a)). Therefore, = 0.0645m = 6.45 cm Consequently, x3 =x2 -r cos0=-2.0 cm - (6.45 cm) cos(-10°) =-8.4 cm, (d) and y; = y2 -r sino= 1.5 cm – (6.45 cm) sin(-10°) = 2.7 cm.
Transcribed Image Text:•15 Go The charges and coordinates of two charged particles held fixed in an xy plane are q = +3.0 µC, x1 = 3.5 cm, y = 0.50 cm, and q2 = -4.0 µC, x, = -2.0 cm, y, = 1.5 cm. Find the (a) magni- tude and (b) direction of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third parti- cle of charge q3 = +4.0 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? Your answer is partially correct. The charges and coordinates of two charged particles held fixed in an xy plane are q1 = 3.11 µC, x1 = 5.01 cm, y1 = 0.163 cm and 92 = -3.84 µC, x2 = -2.24 cm, y2 = 1.95 cm. Find the (a) magnitude and (b) direction (with respect to +x-axis in the range (-180°;180°]) of the electrostatic force on particle 2 due to particle 1. At what (c) x and (d) y coordinates should a third particle of charge q3 - 4.86 µC be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero? (a) Number 19.3 Units N 15. (a) The distance between qi and q2 is (b) Number -13.8 Units * (degrees) rz =(x, -x,)* +(y, -x) =(-0.020 m–0.035 m)* +(0.015 m–0.005 m)* =0.056 m. The magnitude of the force exerted by q, on q; is (c) Number Units -0.095 m (8.99×10°N-m²/C) (3.0×10 C) (4.0×10ʻC) (0.056 m) F =k =35 N. (d) Number 0.037 Units m (b) The vector Ē, is directed toward gj and makes an angle Owith the +x axis, where 972 СНАРТER 21 1.5 cm-0.5 cm 0= tan - = tan =-10.3°-10°. -2.0 cm-3.5 cm (c) Let the third charge be located at (x3, ya), a distance r from q2. We note that qı, 92, and q3 must be collinear; otherwise, an equilibrium position for any one of them would be impossible to find. Furthermore, we cannot place q3 on the same side of q2 where we also find q1, since in that region both forces (exerted on q2 by q3 and qi) would be in the same direction (since qz is attracted to both of them). Thus, in terms of the angle found in part (a), we have x =x -r coso and y "y2 -r sino(which means y3 > y2 since O is negative). The magnitude of force exerted on q2 by q3 is F=k|q:9, Vr, which must equal that of the force exerted on it by q, (found in part (a)). Therefore, = 0.0645m = 6.45 cm Consequently, x3 =x2 -r cos0=-2.0 cm - (6.45 cm) cos(-10°) =-8.4 cm, (d) and y; = y2 -r sino= 1.5 cm – (6.45 cm) sin(-10°) = 2.7 cm.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer