The charged plates of a capacitor attract each other, so to pull the plates farther apart requires work by some external force. What becomes of the energy added by this work? Explain.
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The charged plates of a capacitor attract each other, so to pull
the plates farther apart requires work by some external force. What becomes
of the energy added by this work? Explain.
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- A 12 μF parallel plate capacitor is charged to 200 V and then connected to the 7.0 μF capacitor. The plates are physically pulled apart to double the original separation. a)What is the stored energy? b)Explain the difference in stored energy between the two capacitors. c)Calculate the work performed by the outside agent pulling the plates apart d)The average force exerted on the plates e)The average power if the separation occurs over 10 s.2) You are the owner of a startup company that wants to make a car powered by the energy in a parallel-plate ultracapacitor. If this device stores roughly the same amount of energy as a tank of gasoline (3.0 GJ) when charged to a potential of 100V, what would the area of the plates need to be? Assume a gap of 2nm and that the plates are in a vacuum.2. A capacitor is made from two square conducting plates, each 10 cm x 10 cm, at a separation of 2.0mm. (a) If air is present between the plates, calculate the capacitance. voltage (b) A potential difference-of 80 V is applied to the two plates. How much charge is on each plate? Make a sketch illustrating the charged capacitor. (c) Calculate the electric field in between the capacitor plates. Make a sketch showing field lines. wont ase about dieletricg (d) A dielectric with &,=40 is inserted between the capacitor plates, but to do so, the plate separation must be increased to 2.5 mm. How does the electric field change in this case if the potential difference is kept constant.
- 95.)A sheet of insulating plastic material is inserted between the plates without otherwise disturbing the system What effect does this have on the capacitance? (A) It causes the capacitance to increase. (B) It causes the capacitance to decrease. (C) None; the capacitance does not change. (D) Nothing can be said about the effect without knowing the dielectric constant of the plastic. (E) Nothing can be said about the effect without knowing the thickness of the sheet.A six UF parallel plate capacitor with a dielectric has a charge of 430 uC on each plate the distance between the plates is .006M and the dielectric constant is 12 determine the area of each plate and the E field between the platesA parallel plate capacitor is charged up so that the upper plate carries a charge of 0.2C. In a vacuum, the potential difference between the plates is 2V. When a certain dielectric material is placed between the plates, the potential difference drops to 1.5V. Calculate the dielectric constant of the material.
- Imagine a parallel plate capacitor with mica between the plates. Suppose the potential difference between the plates is 82V, and there is an electric field between the plates with a strength of 320 N/C. If each plate has an area of 0.030 square meters, a) What is the separation between the plates? b) Find the capacitance of the capacitor. c) How much charge is on each plate? d) How much energy is stored in the capacitor? For each part, explain your reasoning.A parallel-plate capacitor is fully charged by a battery. Now the battery is disconnected, and the distance between the plates increases. What happens to the electric field in the capacitor? Answers: stays the same increases decreasesThis question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Oppositely charged parallel plates are separated by 4.59 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.83 mm from the positive plate?