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The center of the circle is located at the x- axis at x=4. If the circle is tangent to the y-axis, what is the equation of the circle? A. x² + (y + 4)² = 16 B. x² + (y – 4)² = 16 C. (x + 4)² + y² = 16 D. (x – 4)2 + y² = 16

The center of the circle is located at the x- axis at x=4. If the circle is tangent to the y-axis, what is the equation of the circle? A. x² + (y + 4)² = 16 B. x² + (y – 4)² = 16 C. (x + 4)² + y² = 16 D. (x – 4)2 + y² = 16

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The center of the circle is located at the x- axis at x=4. If the circle is tangent to the y-axis, what is the equation of the circle? А. х2 + (у + 4)2 %3D 16 В. х2 + (у — 4)2 3D 16 C. (x + 4)2 + y? = 16 D. (x — 4)2 + yу? 3D 16 A farmer is building a circular corral to hold a livestock. He located the four post at (8,0) , (-8,0) , (0,8), and (0,-8) and each post is an endpoint of a diameter with distances measured in meters. Find the length of fencing required for the circular corral. A. 30.5 meters B. 35.0 meters C. 50.3 meters D. 53.0 meters A bank of lights is arranged over a stage. Each light illuminates a circular area on the stage. A coordinate plane is used to arrange the lights, using the corner of stage as the origin. The equation (x - of light. If three actors are located on three different spots Gelan (11,4) , Jr (8,5) and 13)? + (y - 4)2 = 16 represents one of the disks Galford (15,5). Which actors is in the disc of light? A. Gelan and Jr C. Gelan and Galford B. Jr and Galford D. The three actors are in the disc of light The equation of the circle А. х2 + у? + 24х + 6у + 137 3D 0 В. х2 + у? — 24х + 6у + 137 3 0 С. х2 + у2 — 24х — бу + 137 — 0 D. x² + y? + 24x – 6y + 137 = 0 The area of the circle x? + y? + 4x – 6y – 12 = 0 . (A = ar²) С. А 3D 16п square units D. A = 257 square units Α. Α4π square units В. А 3D 9п square units Find the equation of the circle, if the circle x? + y? + 14x + 12y + 76 = 0 is translated 2 units to the right and 4 units downward. A. (x + 5)2 + (y + 10)² = 9 B. (x + 5)? + (y – 10)2 = 9 C. (x – 5)2 + (y – 10)? = 9 D. (x – 5)? + (y + 10)? = 9 The center and radius of the circle (x – 5)2 + (y + 3)² = 13. A. Center (-5,3), radius = 13 units C. Center (-5,3), radius = V13 units D. Center (5, –3), radius = V13 units B. Center (5,-3),radius = 13 units
Transcribed Image Text:The center of the circle is located at the x- axis at x=4. If the circle is tangent to the y-axis, what is the equation of the circle? А. х2 + (у + 4)2 %3D 16 В. х2 + (у — 4)2 3D 16 C. (x + 4)2 + y? = 16 D. (x — 4)2 + yу? 3D 16 A farmer is building a circular corral to hold a livestock. He located the four post at (8,0) , (-8,0) , (0,8), and (0,-8) and each post is an endpoint of a diameter with distances measured in meters. Find the length of fencing required for the circular corral. A. 30.5 meters B. 35.0 meters C. 50.3 meters D. 53.0 meters A bank of lights is arranged over a stage. Each light illuminates a circular area on the stage. A coordinate plane is used to arrange the lights, using the corner of stage as the origin. The equation (x - of light. If three actors are located on three different spots Gelan (11,4) , Jr (8,5) and 13)? + (y - 4)2 = 16 represents one of the disks Galford (15,5). Which actors is in the disc of light? A. Gelan and Jr C. Gelan and Galford B. Jr and Galford D. The three actors are in the disc of light The equation of the circle А. х2 + у? + 24х + 6у + 137 3D 0 В. х2 + у? — 24х + 6у + 137 3 0 С. х2 + у2 — 24х — бу + 137 — 0 D. x² + y? + 24x – 6y + 137 = 0 The area of the circle x? + y? + 4x – 6y – 12 = 0 . (A = ar²) С. А 3D 16п square units D. A = 257 square units Α. Α4π square units В. А 3D 9п square units Find the equation of the circle, if the circle x? + y? + 14x + 12y + 76 = 0 is translated 2 units to the right and 4 units downward. A. (x + 5)2 + (y + 10)² = 9 B. (x + 5)? + (y – 10)2 = 9 C. (x – 5)2 + (y – 10)? = 9 D. (x – 5)? + (y + 10)? = 9 The center and radius of the circle (x – 5)2 + (y + 3)² = 13. A. Center (-5,3), radius = 13 units C. Center (-5,3), radius = V13 units D. Center (5, –3), radius = V13 units B. Center (5,-3),radius = 13 units
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