The center of gravity of the 3000-lb car is at G. The car is parked on an incline with the parking brake engaged, which locks the rear wheels. Find (a) the normal forces (perpendicular to the incline) acting under the front and rear pairs of wheels; and (b) the friction force (parallel to the incline) under the rear pair of wheels. 2.2 ft A N₁ W cos(12) W -3 ft- W sin (12) 6 ft 4₂ N₂ x-axis y-axis 12°

The center of gravity of the 3000-lb car is at G. The car is parked on an incline with the parking brake engaged, which locks the rear wheels. Find (a) the normal forces (perpendicular to the incline) acting under the front and rear pairs of wheels; and (b) the friction force (parallel to the incline) under the rear pair of wheels. 2.2 ft A N₁ W cos(12) W -3 ft- W sin (12) 6 ft 4₂ N₂ x-axis y-axis 12°

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Center of Gravity and Centroid

The term center of gravity indicates the position or location of a point about which the whole weight of a body or system is supposed to be concentrated, which means the whole weight of the body or system works through this point. It is closely related to mass distribution. For all positions of the body, the center of gravity would be a single point.

Question

[Chapter 4, Problem 4.41P
The center of gravity of the 3000-lb car is at G. The car is parked on an incline with the parking brake
engaged, which locks the rear wheels. Find (a) the normal forces (perpendicular to the incline) acting under
the front and rear pairs of wheels; and (b) the friction force (parallel to the incline) under the rear pair of
wheels.
2.2 ft
A
N₁
W cos(12) W
-3 ft-
-
W sin (12)
6 ft
f
44
N₂
x-axis
y-axis
12°

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