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The cell: SCE//HA(0.250M), NaA(0.170M)/H2(1.00bar), Pt has a poten- tial of -0.721V at 298K. (The SCE electrode potential is +0.2444V) (a) Sketch this cell. (b) What is potential of this cell vs. Ag/AgCl/sat'd KCI? (c) Calculate the dissociation constant of HA neglecting the junction poten-

The cell: SCE//HA(0.250M), NaA(0.170M)/H2(1.00bar), Pt has a poten- tial of -0.721V at 298K. (The SCE electrode potential is +0.2444V) (a) Sketch this cell. (b) What is potential of this cell vs. Ag/AgCl/sat'd KCI? (c) Calculate the dissociation constant of HA neglecting the junction poten-

Principles of Instrumental Analysis
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter23: Potentiometry
Section: Chapter Questions
Problem 23.23QAP: The following cell was found to have a potential of —0.492 V: Ag|AgCl(sat’d)||HA(0.200 M),NaA(0.300...
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The cell: SCE//HA(0.250M), Na A(0.170M)/H2(1.00bar), Pt has a poten- tial of -0.721V at 298K. (The SCE electrode potential is +0.2444V) (a) Sketch this cell. (b) What is potential of this cell vs. Ag/AgCl/sat'd KCI? (c) Calculate the dissociation constant of HA neglecting the junction poten- tial.
Transcribed Image Text:The cell: SCE//HA(0.250M), Na A(0.170M)/H2(1.00bar), Pt has a poten- tial of -0.721V at 298K. (The SCE electrode potential is +0.2444V) (a) Sketch this cell. (b) What is potential of this cell vs. Ag/AgCl/sat'd KCI? (c) Calculate the dissociation constant of HA neglecting the junction poten- tial.
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