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the cell: pt / H₂ (latim) / NaOH cm) / HgO cs) / Hg = 0.924V 0.854 V and Егадк Calculate standard electromoting Hg/ Hg2+ + force E2. 298 K write the electrods reactions and the cell reaction Sor calculate the electromotive force at 308 K when cell reactio the change in inthalpy (AH) = - 35 kcal nd, what happen to electromotive force when added few amount of nitric acid to equivalent to the base NaOH partially 2 2

the cell: pt / H₂ (latim) / NaOH cm) / HgO cs) / Hg = 0.924V 0.854 V and Егадк Calculate standard electromoting Hg/ Hg2+ + force E2. 298 K write the electrods reactions and the cell reaction Sor calculate the electromotive force at 308 K when cell reactio the change in inthalpy (AH) = - 35 kcal nd, what happen to electromotive force when added few amount of nitric acid to equivalent to the base NaOH partially 2 2

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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For the cell: pt / H₂ (latm) / NaOH cm) / HgO (s) / Hg EHg / Hg²+ Егадк = 0.924V 2+ + 0.854 V calculate standard electromotive force E298 K write the electrods reactions and the cell the cell reaction. So calculate the electromotive force at 308 K when the change in inthalpy (AH) = and, what happen to electromotive force when added few amount of nitric acid to equivalent to the base NaOH partially? 35 Kcal Cell reaction - and
Transcribed Image Text:For the cell: pt / H₂ (latm) / NaOH cm) / HgO (s) / Hg EHg / Hg²+ Егадк = 0.924V 2+ + 0.854 V calculate standard electromotive force E298 K write the electrods reactions and the cell the cell reaction. So calculate the electromotive force at 308 K when the change in inthalpy (AH) = and, what happen to electromotive force when added few amount of nitric acid to equivalent to the base NaOH partially? 35 Kcal Cell reaction - and
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