The car's corner mass is m₁ = 220 kg and the unsprung mass is m₂ = 16 kg. The suspension spring stiffness is k = 13000 N/m and the tire stiffness is k, = 150000 N/m. a) Find the ride rate, RR, in N/m. b) Find the bounce natural frequency, f, in Hz for this corner of the car. c) Find the value of the suspension damping coefficient, c, that corresponds to a suspension damping ratio of 5 = 0.5. d) Find the damped natural frequency, fa, in Hz if the damping ratio is 5 = 0.5.

The car's corner mass is m₁ = 220 kg and the unsprung mass is m₂ = 16 kg. The suspension spring stiffness is k = 13000 N/m and the tire stiffness is k, = 150000 N/m. a) Find the ride rate, RR, in N/m. b) Find the bounce natural frequency, f, in Hz for this corner of the car. c) Find the value of the suspension damping coefficient, c, that corresponds to a suspension damping ratio of 5 = 0.5. d) Find the damped natural frequency, fa, in Hz if the damping ratio is 5 = 0.5.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free undamped vibrations

Whenever an object/system displaces in either side of its equilibrium position with the help of an external/internal means, then the object/system moves regularly or randomly on both sides of its equilibrium position. This motion is called vibration. Generally, there are three types of vibration: longitudinal vibration, transverse vibration, and torsional vibration.

Question

The car's corner mass is m₁ = 220 kg and the unsprung mass is m₂ = 16 kg . The
suspension spring stiffness is k = 13000 N/m and the tire stiffness is k, = 150000 N/m.
a) Find the ride rate, RR, in N/m.
b) Find the bounce natural frequency, f, in Hz for this corner of the car.
c) Find the value of the suspension damping coefficient, c, that corresponds to a
suspension damping ratio of 5 = 0.5.
d) Find the damped natural frequency, fa, in Hz if the damping ratio is 5 = 0.5.
m₂
k₂
m₁
III
Jizz
Z2
z, (t) = A, sin ot

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