The car A has a forward speed of 21 km/h and is accelerating at 3.0 m/s². Determine the velocity and acceleration of the car relative to observer B, who rides in a nonrotating chair on the Ferris wheel. The angular rate = 3.2 rev/min of the Ferris wheel is constant.

Elements Of Electromagnetics
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### Ferris Wheel Car Problem

**Problem Statement:**

The car A has a forward speed of 21 km/h and is accelerating at 3.0 m/s². Determine the velocity and acceleration of the car relative to observer B, who rides in a non-rotating chair on the Ferris wheel. The angular rate Ω = 3.2 rev/min of the Ferris wheel is constant.

**Diagram:**

![Diagram](image-link)

- The Ferris wheel has a radius \( R = 8.4 \) m.
- The angle at which the observer B is located from the horizontal axis is 44°.
- The Ferris wheel has an angular rate \( \Omega = 3.2 \) rev/min.
- The car A is moving along a straight path on the ground.

**Given:**

- Forward Speed of Car A: 21 km/h (convert to m/s: \( 21 \times \frac{1000}{3600} = 5.83 \) m/s)
- Acceleration of Car A: 3.0 m/s²
- Radius of Ferris wheel: \( R = 8.4 \) m
- Angular rate: \( \Omega = 3.2 \) rev/min (convert to rad/s: \( 3.2 \times \frac{2\pi}{60} = 0.335 \) rad/s)
- Angle: 44°

### Answers:

**Velocity ( \(v_{A/B}\) ):**

\[ v_{A/B} = \begin{pmatrix} 3.878 \\ 2.025 \end{pmatrix} \text{ m/s} \]

**Acceleration ( \(a_{A/B}\) ):**

\[ a_{A/B} = \begin{pmatrix} 3.723 \\ -0.606 \end{pmatrix} \text{ m/s}² \]

### Explanation of the Diagram:

1. **Ferris Wheel**: The large circle represents the Ferris wheel. The radius of the wheel is labeled as \( R = 8.4 \) m.
2. **Car A**: The car is shown on a straight path at the base of the Ferris wheel.
3. **Observer B**: Located at an angle of 44° above the horizontal axis on the Ferris wheel.
4. **Angular Rate**: Indicated as
Transcribed Image Text:### Ferris Wheel Car Problem **Problem Statement:** The car A has a forward speed of 21 km/h and is accelerating at 3.0 m/s². Determine the velocity and acceleration of the car relative to observer B, who rides in a non-rotating chair on the Ferris wheel. The angular rate Ω = 3.2 rev/min of the Ferris wheel is constant. **Diagram:** ![Diagram](image-link) - The Ferris wheel has a radius \( R = 8.4 \) m. - The angle at which the observer B is located from the horizontal axis is 44°. - The Ferris wheel has an angular rate \( \Omega = 3.2 \) rev/min. - The car A is moving along a straight path on the ground. **Given:** - Forward Speed of Car A: 21 km/h (convert to m/s: \( 21 \times \frac{1000}{3600} = 5.83 \) m/s) - Acceleration of Car A: 3.0 m/s² - Radius of Ferris wheel: \( R = 8.4 \) m - Angular rate: \( \Omega = 3.2 \) rev/min (convert to rad/s: \( 3.2 \times \frac{2\pi}{60} = 0.335 \) rad/s) - Angle: 44° ### Answers: **Velocity ( \(v_{A/B}\) ):** \[ v_{A/B} = \begin{pmatrix} 3.878 \\ 2.025 \end{pmatrix} \text{ m/s} \] **Acceleration ( \(a_{A/B}\) ):** \[ a_{A/B} = \begin{pmatrix} 3.723 \\ -0.606 \end{pmatrix} \text{ m/s}² \] ### Explanation of the Diagram: 1. **Ferris Wheel**: The large circle represents the Ferris wheel. The radius of the wheel is labeled as \( R = 8.4 \) m. 2. **Car A**: The car is shown on a straight path at the base of the Ferris wheel. 3. **Observer B**: Located at an angle of 44° above the horizontal axis on the Ferris wheel. 4. **Angular Rate**: Indicated as
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