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The capacitor in the circuit below has an initial voltage of 10 V across it, i.e., v(0)=10V. The switch SW1 is closed at time t=0. a. Use KCL to show that the governing equation for the voltage v(t) is given by dv RC + v = 5 dt b. Solve this governing equation to find v(t) for t>0. What is the time constant? c. Plot v(t) between 0

The capacitor in the circuit below has an initial voltage of 10 V across it, i.e., v(0)=10V. The switch SW1 is closed at time t=0. a. Use KCL to show that the governing equation for the voltage v(t) is given by dv RC + v = 5 dt b. Solve this governing equation to find v(t) for t>0. What is the time constant? c. Plot v(t) between 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The capacitor in the circuit below has an initial voltage of 10 V across it, i.e., v(0)=10V. The switch SW1 is closed at time t=0. a. Use KCL to show that the governing equation for the voltage v(t) is given by dv RC +v=5 dt i_c b. c. Solve this governing equation to find v(t) for t>0. What is the time constant? Plot v(t) between 0<t<3t. v(t) 1 µF SW1 i_R 1 ΚΩ +5V
Transcribed Image Text:The capacitor in the circuit below has an initial voltage of 10 V across it, i.e., v(0)=10V. The switch SW1 is closed at time t=0. a. Use KCL to show that the governing equation for the voltage v(t) is given by dv RC +v=5 dt i_c b. c. Solve this governing equation to find v(t) for t>0. What is the time constant? Plot v(t) between 0<t<3t. v(t) 1 µF SW1 i_R 1 ΚΩ +5V
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