The cantilever beam consists of a rectangular structural steel tube shape [E = 200 GPa; I = 425 × 106 mm4]. Assume P = 35 kN, w = 10 kN/m, LAB = 1.50 m, and LBC = 2.00 m. Using Appendix C and method of superposition, determine: (a) the beam deflection at point A. [vA = -4.54 mm] (b) the beam deflection at point B.
The cantilever beam consists of a rectangular structural steel tube shape [E = 200 GPa; I = 425 × 106 mm4]. Assume P = 35 kN, w = 10 kN/m, LAB = 1.50 m, and LBC = 2.00 m. Using Appendix C and method of superposition, determine: (a) the beam deflection at point A. [vA = -4.54 mm] (b) the beam deflection at point B.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
The cantilever beam consists of a rectangular structural steel tube shape [E = 200 GPa; I = 425 × 106 mm4]. Assume P = 35 kN, w = 10 kN/m, LAB = 1.50 m, and LBC = 2.00 m. Using Appendix C and method of superposition, determine:
(a) the beam deflection at point A. [vA = -4.54 mm]
(b) the beam deflection at point B. [vB = -2.07 mm]
![P
C
A
B
LAB
LBC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcbe28e7d-3aef-4872-ab00-51e651b837bf%2Fad648294-8de4-40c0-9f17-a524bb984de4%2Fdc8bv7i_processed.png&w=3840&q=75)
Transcribed Image Text:P
C
A
B
LAB
LBC
![Beam
Slope
Deflection
Elastic Curve
PL
Px?
-(3L – x)
6EI
PL?
0max =
Vmax =
y =
Vmax.
2EI
ЗЕ
Omax
Px2
-(3L – 2x)
12EI
for 0 <x S
y = -
PL?
5PL?
0max =
Vmax =
8 ΕΙ
48EI
PL?
- (6х — L)
48EI
Vmax
V = -
for
emax
Mx?
V = -
2EI
ML
ML?
0max =
Vmax =
Vmax.
EI
2EI
Omax
wL
wx?
(6L? – 4Lx + x²)
24EI
wL
10
0max =
Vmax =
V =
6EI
8EI
,'max
max
Wo
Wox?
-(10L – 10L?x + 5Lx² – x³)
11
0max =
Vmax =
24EI
30EI
120LEI
Vmax
Pmax](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcbe28e7d-3aef-4872-ab00-51e651b837bf%2Fad648294-8de4-40c0-9f17-a524bb984de4%2Fqk38nz_processed.png&w=3840&q=75)
Transcribed Image Text:Beam
Slope
Deflection
Elastic Curve
PL
Px?
-(3L – x)
6EI
PL?
0max =
Vmax =
y =
Vmax.
2EI
ЗЕ
Omax
Px2
-(3L – 2x)
12EI
for 0 <x S
y = -
PL?
5PL?
0max =
Vmax =
8 ΕΙ
48EI
PL?
- (6х — L)
48EI
Vmax
V = -
for
emax
Mx?
V = -
2EI
ML
ML?
0max =
Vmax =
Vmax.
EI
2EI
Omax
wL
wx?
(6L? – 4Lx + x²)
24EI
wL
10
0max =
Vmax =
V =
6EI
8EI
,'max
max
Wo
Wox?
-(10L – 10L?x + 5Lx² – x³)
11
0max =
Vmax =
24EI
30EI
120LEI
Vmax
Pmax
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