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The cable BC carries a tension of 750 N.
Determine the projection of the tension on
the line BO and find the angle between
them.
1.2 m
1.6 m
с
0.7 m
B
OT BO=555.16 N,0=42.25
OT BO=500.16 N,0=25.25
OT BO=-598i+411j+189.5k N,0=42.25
30°
0.8m

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