The butt connection shows 8-22 mm diameter bolts spaced as shown below. P 50 100 50 50 100 50 ## 00 O 16 mm 00 O O 40 80 40 12 mm Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. -P -P Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions:

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Kindly use the pattern for solving the problem.
The butt connection shows 8-22 mm diameter bolts spaced as
shown below.
P
50 100 50 50 100 50
16 mm
O
Based on the gross area of the plate.
Based on the net area of the plate.
Based on block shear strength.
40
80
40
off
O
=
12 mm
P
Steel strength and stresses are:
Yield strength, Fy = 248 MPa
Ultimate strength, Fu = 400 MPa
Allowable tensile stress on the gross area = 148 MPa
Allowable tensile stress on the net area
200 MPa
Allowable shear stress on the net area = 120 MPa
Allowable bolt shear stress, Fv = 120 MPa
Bolt hole diameter = 25 mm
Calculate the allowable tensile load, P, under the following
conditions:
P
Transcribed Image Text:The butt connection shows 8-22 mm diameter bolts spaced as shown below. P 50 100 50 50 100 50 16 mm O Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. 40 80 40 off O = 12 mm P Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions: P
The butt connection shows 8-22 mm diameter bolts spaces as shown below. Steel strengths are F, = 248 MPa
and F₁ = 400 MPa. Calculate the design tensile strength based on the following:
bolt hole diameter = 25mm
Based on the gross area of the plate
Based on the net area of the plate.
Based on block shear strength.
P
P4
16 mm
16 mm
Based on the gross area of the plate.
50 100 50 50 100 50
Based on the net area of the plate.
.
Shear lag factor, W: 1.0
An
Ph 0.75 Ph 0.5 Fu Ac = 0.5 Fu UAN
Based on block shear strength.
LUL
2
>
160 (16) 2(25) (16) = 1760 mm ²
Ø Pn = 0.75 (400) (1.0) (1760)/1000 = 528 KA
.: R= 885. 12 KW
Pm 0.9Pn= 0.9 Fylg = 0.9 (248) (160) (16)/1000 = 571. 392 kW
=
Ph
+P/₂
=
*
Anr
Amr
Up=1-0; Fy= 248; Fu = 400 mpa
Am[1501.5 (25)] 16 (2) = 3600
Agv = 150 (16) (2) 4800
Ant (8025) (16) 8.80 MM ²
- mm
Agr
40
Any
3600
Agv = 4800
Ant = (80-25) (1) = 880mm ²
80
Agv = 100 (16) = 1600
-
Anb
40
Stress:
Outer Plate
6.
P/₂
w (12)
12 mm
Anv [150-15 (25)] 16 = 1800 fram ²
Agv = 150 (16) = 2400
Ant = [120 - 1.5 (25)] 16 = 1320mm ²
DERM
0₂R = 0.75Rm = 663.84KN
2
= (100- 25) (16) = 1200
2
Ant (160-2(25)) (16) = 1760 mm)
=
P
P
24W
middle plate
6 = P
P
3
W (16) 16 W
R,₁,-0.6FA+USFUAM = 12160KN)
0.6F,A+UFA 1066-240
R = 0.6FA+UFμAni= 1216.0KN)
0.6F,A+UFA 1066-240
R = 0.6FA+U₂₂FA = 960 kW
0.6F,A+UFA 885.12K
R₁ -0.6F,A+UFAL = 992.0ku
0.6F,A+UFA = 942.08k
Transcribed Image Text:The butt connection shows 8-22 mm diameter bolts spaces as shown below. Steel strengths are F, = 248 MPa and F₁ = 400 MPa. Calculate the design tensile strength based on the following: bolt hole diameter = 25mm Based on the gross area of the plate Based on the net area of the plate. Based on block shear strength. P P4 16 mm 16 mm Based on the gross area of the plate. 50 100 50 50 100 50 Based on the net area of the plate. . Shear lag factor, W: 1.0 An Ph 0.75 Ph 0.5 Fu Ac = 0.5 Fu UAN Based on block shear strength. LUL 2 > 160 (16) 2(25) (16) = 1760 mm ² Ø Pn = 0.75 (400) (1.0) (1760)/1000 = 528 KA .: R= 885. 12 KW Pm 0.9Pn= 0.9 Fylg = 0.9 (248) (160) (16)/1000 = 571. 392 kW = Ph +P/₂ = * Anr Amr Up=1-0; Fy= 248; Fu = 400 mpa Am[1501.5 (25)] 16 (2) = 3600 Agv = 150 (16) (2) 4800 Ant (8025) (16) 8.80 MM ² - mm Agr 40 Any 3600 Agv = 4800 Ant = (80-25) (1) = 880mm ² 80 Agv = 100 (16) = 1600 - Anb 40 Stress: Outer Plate 6. P/₂ w (12) 12 mm Anv [150-15 (25)] 16 = 1800 fram ² Agv = 150 (16) = 2400 Ant = [120 - 1.5 (25)] 16 = 1320mm ² DERM 0₂R = 0.75Rm = 663.84KN 2 = (100- 25) (16) = 1200 2 Ant (160-2(25)) (16) = 1760 mm) = P P 24W middle plate 6 = P P 3 W (16) 16 W R,₁,-0.6FA+USFUAM = 12160KN) 0.6F,A+UFA 1066-240 R = 0.6FA+UFμAni= 1216.0KN) 0.6F,A+UFA 1066-240 R = 0.6FA+U₂₂FA = 960 kW 0.6F,A+UFA 885.12K R₁ -0.6F,A+UFAL = 992.0ku 0.6F,A+UFA = 942.08k
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