Kindly use the pattern for solving the problem. The butt connection shows 8-22 mm diameter bolts spaced asshown below.P50 100 50 50 100 5016 mmOBased on the gross area of the plate.Based on the net area of the plate.Based on block shear strength.408040offO=12 mmPSteel strength and stresses are:Yield strength, Fy = 248 MPaUltimate strength, Fu = 400 MPaAllowable tensile stress on the gross area = 148 MPaAllowable tensile stress on the net area200 MPaAllowable shear stress on the net area = 120 MPaAllowable bolt shear stress, Fv = 120 MPaBolt hole diameter = 25 mmCalculate the allowable tensile load, P, under the followingconditions:P The butt connection shows 8-22 mm diameter bolts spaces as shown below. Steel strengths are F, = 248 MPaand F₁ = 400 MPa. Calculate the design tensile strength based on the following:bolt hole diameter = 25mmBased on the gross area of the plateBased on the net area of the plate.Based on block shear strength.PP416 mm16 mmBased on the gross area of the plate.50 100 50 50 100 50Based on the net area of the plate..Shear lag factor, W: 1.0AnPh 0.75 Ph 0.5 Fu Ac = 0.5 Fu UANBased on block shear strength.LUL2>160 (16) 2(25) (16) = 1760 mm ²Ø Pn = 0.75 (400) (1.0) (1760)/1000 = 528 KA.: R= 885. 12 KWPm 0.9Pn= 0.9 Fylg = 0.9 (248) (160) (16)/1000 = 571. 392 kW=Ph+P/₂=*AnrAmrUp=1-0; Fy= 248; Fu = 400 mpaAm[1501.5 (25)] 16 (2) = 3600Agv = 150 (16) (2) 4800Ant (8025) (16) 8.80 MM ²- mmAgr40Any3600Agv = 4800Ant = (80-25) (1) = 880mm ²80Agv = 100 (16) = 1600-Anb40Stress:Outer Plate6.P/₂w (12)12 mmAnv [150-15 (25)] 16 = 1800 fram ²Agv = 150 (16) = 2400Ant = [120 - 1.5 (25)] 16 = 1320mm ²DERM0₂R = 0.75Rm = 663.84KN2= (100- 25) (16) = 12002Ant (160-2(25)) (16) = 1760 mm)=PP24Wmiddle plate6 = PP3W (16) 16 WR,₁,-0.6FA+USFUAM = 12160KN)0.6F,A+UFA 1066-240R = 0.6FA+UFμAni= 1216.0KN)0.6F,A+UFA 1066-240R = 0.6FA+U₂₂FA = 960 kW0.6F,A+UFA 885.12KR₁ -0.6F,A+UFAL = 992.0ku0.6F,A+UFA = 942.08k

Given:- The yield strength of steel (Fy) = 248 MPa The ultimate strength of steel (Fu) = 400 MPa The…

The butt connection shows 8-22 mm diameter bolts spaced as shown below. P 50 100 50 50 100 50 ## 00 O 16 mm 00 O O 40 80 40 12 mm Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. -P -P Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions:

The butt connection shows 8-22 mm diameter bolts spaced as shown below. P 50 100 50 50 100 50 ## 00 O 16 mm 00 O O 40 80 40 12 mm Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. -P -P Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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