The building frame shown in the figure below is constructed using rigid girders and flexible columns. The weight of the floor is 130 kN. The frame is subjected to a harmonic force, as schematically shown in the figure. Evaluate the steady state response of the frame assuming Fo = 80 kN and period of the external force T = 2 seconds. For the frame, assume that E = 200 GPa, damping ratio = 0.1, height of the end columns Hj = 4 m, height of the central column H2= 6 m, and span of the beam L = 6 m. The values of the moment of inertia of the columns are also known: = 2.6 10* mm* for the end columns and I= 3.254•10* mm“ for the central column. F(t) = Fo sin(wt)
The building frame shown in the figure below is constructed using rigid girders and flexible columns. The weight of the floor is 130 kN. The frame is subjected to a harmonic force, as schematically shown in the figure. Evaluate the steady state response of the frame assuming Fo = 80 kN and period of the external force T = 2 seconds. For the frame, assume that E = 200 GPa, damping ratio = 0.1, height of the end columns Hj = 4 m, height of the central column H2= 6 m, and span of the beam L = 6 m. The values of the moment of inertia of the columns are also known: = 2.6 10* mm* for the end columns and I= 3.254•10* mm“ for the central column. F(t) = Fo sin(wt)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Problem 3
The building frame shown in the figure below is constructed using rigid girders and flexible
columns. The weight of the floor is 130 kN. The frame is subjected to a harmonic force, as
schematically shown in the figure. Evaluate the steady state response of the frame assuming Fo =
80 kN and period of the external force T = 2 seconds. For the frame, assume that E = 200 GPa,
damping ratio = 0.1, height of the end columns H1 = 4 m, height of the central column H2= 6 m,
and span of the beam L = 6 m. The values of the moment of inertia of the columns are also known:
I= 2.6 10* mm* for the end columns and I = 3.254 10* mm“ for the central column.
F(t) = F, sin(wt)
m
E, I
E, I
H2
E, I H,
L
ui
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