the bu you ne 4. Prove that the LHS is equal to the RHS. csc A-cot A a. = cot A sec A-1 1-tan² A b. = cot 2A 2 tan A sin A+ 1 1-sin A C. 4 sec A tan A 1-sin A sin A+1 - est foot.
the bu you ne 4. Prove that the LHS is equal to the RHS. csc A-cot A a. = cot A sec A-1 1-tan² A b. = cot 2A 2 tan A sin A+ 1 1-sin A C. 4 sec A tan A 1-sin A sin A+1 - est foot.
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
Answer only number 4
![Answer the following items. Show all necessary solutions.
1. A passenger ship sails from a point A on a bearing of 038°T for
4km to a point B. At B the ship changes course and sails for 6km
on a bearing of 156ºT to a point C. Find the distance AC and the
bearing of A from C.
2. Peter observes that the bearing to a resort from his current
position is to be S43°W. He proceeds to hike 3 miles at a bearing
of S23ºE at which point he determines the bearing to the resort to
be S78°W. How far is Peter from the resort at this point? Round
your answer to the nearest mile.
3. From a point on the ground, the angle of elevation of the top of
the building is 65º. Moving 196 ft. farther from the building, the
angle of elevation to the top of the building is now 47º. How tall is
the building? Round your answer to the nearest foot.
4. Prove that the LHS is equal to the RHS.
csc A-cot A
a.
= cot A
sec A-1
1-tan² A
b.
= cot 2A
2 tan A
sin A+1
1-sin A
C.
= 4 sec A tan A
1-sin A
sin A+1
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f82bb57-f1b0-47a5-a826-0a0f4675b71b%2Fc47abe24-efcc-4c9a-8847-bf06441725a6%2Fcznwvk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Answer the following items. Show all necessary solutions.
1. A passenger ship sails from a point A on a bearing of 038°T for
4km to a point B. At B the ship changes course and sails for 6km
on a bearing of 156ºT to a point C. Find the distance AC and the
bearing of A from C.
2. Peter observes that the bearing to a resort from his current
position is to be S43°W. He proceeds to hike 3 miles at a bearing
of S23ºE at which point he determines the bearing to the resort to
be S78°W. How far is Peter from the resort at this point? Round
your answer to the nearest mile.
3. From a point on the ground, the angle of elevation of the top of
the building is 65º. Moving 196 ft. farther from the building, the
angle of elevation to the top of the building is now 47º. How tall is
the building? Round your answer to the nearest foot.
4. Prove that the LHS is equal to the RHS.
csc A-cot A
a.
= cot A
sec A-1
1-tan² A
b.
= cot 2A
2 tan A
sin A+1
1-sin A
C.
= 4 sec A tan A
1-sin A
sin A+1
-
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