The British Department of Transportation studied to see if people avoid driving on Friday the 13th.   They did a traffic count on a Friday and then again on a Friday the 13th at the same two locations ("Friday the 13th," 2013).  The data for each location on the two different dates is in following table: Table: Traffic Count Dates 6th 13th 1990, July 139246 138548 1990, July 134012 132908 1991, September 137055 136018 1991, September 133732 131843 1991, December 123552 121641 1991, December 121139 118723 1992, March 128293 125532 1992, March 124631 120249 1992, November 124609 122770 1992, November 117584 117263  Let μ1 = mean traffic count on Friday the 6th.  Let μ2 =  mean traffic count on Friday the 13th.  Estimate the mean difference in traffic count between the 6th and the 13th using a 90% level.    (vii)  Determine confidence interval of the mean difference μd Enter lower bound value to nearest tenth, followed by < , followed by "μd" for mean difference, followed by <, followed by upper bound value to nearest tenth.  No spaces between any characters. Use "negative" sign if necessary.  Do not use italics or enter units of measure.  Examples of correctly entered answers: 0.74<μd<0.78 13.14<μd<13.96 -9.72<μd<-8.08    (viii)  Using the confidence interval, select the correct description of the result of the survey: A.  We estimate with 90% confidence that the true population mean traffic count between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5. B.  We estimate with 90% confidence that the true mean difference in traffic counts between Friday the 6th and Friday the 13th falls outside 1154.1 and 2517.5. C.  We estimate with 90% confidence that the true sample mean traffic counts between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5. D.  We estimate with 90% confidence that the true mean difference in traffic counts between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5. Enter letter corresponding to most correct answer

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The British Department of Transportation studied to see if people avoid driving on Friday the 13th.   They did a traffic count on a Friday and then again on a Friday the 13th at the same two locations ("Friday the 13th," 2013).  The data for each location on the two different dates is in following table:

Table: Traffic Count

Dates

6th

13th

1990, July

139246

138548

1990, July

134012

132908

1991, September

137055

136018

1991, September

133732

131843

1991, December

123552

121641

1991, December

121139

118723

1992, March

128293

125532

1992, March

124631

120249

1992, November

124609

122770

1992, November

117584

117263

 Let μ1 = mean traffic count on Friday the 6th.  Let μ2 =  mean traffic count on Friday the 13th.  Estimate the mean difference in traffic count between the 6th and the 13th using a 90% level.

 

 (vii)  Determine confidence interval of the mean difference μd

Enter lower bound value to nearest tenth, followed by < , followed by "μd" for mean difference, followed by <, followed by upper bound value to nearest tenth.  No spaces between any characters. Use "negative" sign if necessary.  Do not use italics or enter units of measure.  Examples of correctly entered answers:

0.74<μd<0.78

13.14<μd<13.96

-9.72<μd<-8.08

 

 (viii)  Using the confidence interval, select the correct description of the result of the survey:

A.  We estimate with 90% confidence that the true population mean traffic count between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5.

B.  We estimate with 90% confidence that the true mean difference in traffic counts between Friday the 6th and Friday the 13th falls outside 1154.1 and 2517.5.

C.  We estimate with 90% confidence that the true sample mean traffic counts between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5.

D.  We estimate with 90% confidence that the true mean difference in traffic counts between Friday the 6th and Friday the 13th is between 1154.1 and 2517.5.

Enter letter corresponding to most correct answer

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