The box shown in the figure is being accelerated by pulling on it with the rope. (a) Assume the floor is frictionless. What is the maximum force that can be applied without causing the box to tip over? (b) Repeat part a, but now let the coefficient of friction be µ. (c) What happens to your answer to part b when the box is sufficiently tall? How do you interpret this?
The box shown in the figure is being accelerated by pulling on it with the rope. (a) Assume the floor is frictionless. What is the maximum force that can be applied without causing the box to tip over? (b) Repeat part a, but now let the coefficient of friction be µ. (c) What happens to your answer to part b when the box is sufficiently tall? How do you interpret this?
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The box shown in the figure is being accelerated by pulling on it with the rope.
(a) Assume the floor is frictionless. What is
the maximum force that can be applied without causing the box to tip over?
(b) Repeat part a, but now let the coefficient of
friction be µ.
(c) What happens to your answer to part b when
the box is sufficiently tall? How do you interpret
this?

Transcribed Image Text:9-v4
The box shown in the figure is being ac-
celerated by pulling on it with the rope.
(a) Assume the floor is frictionless. What is
the maximum force that can be applied with-
out causing the box to tip over?
(b) Repeat part a, but now let the coefficient of
friction be u.
(c) What happens to your answer to part b when
the box is sufficiently tall? How do you interpret
this?
2a
m
2b
Problem 9-v4.
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