the bottom of the wire, the bead is loaded against a spring with spring constant k = 1000 N/m. The spring is pulled back a distance of 15 cm from its uncompressed length. When the spring is released, the bead is launched up the wire having a curve described by the equation y = 1.5 sin (*) TX where y is in meters, and L = 2.0 m. %3D What are the normal and tangential forces (magnitude and direction) acting on the bead when it is at x = 0.70 m?
the bottom of the wire, the bead is loaded against a spring with spring constant k = 1000 N/m. The spring is pulled back a distance of 15 cm from its uncompressed length. When the spring is released, the bead is launched up the wire having a curve described by the equation y = 1.5 sin (*) TX where y is in meters, and L = 2.0 m. %3D What are the normal and tangential forces (magnitude and direction) acting on the bead when it is at x = 0.70 m?
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Transcribed Image Text:A bead of mass 0.40 kg can slide frictionlessly along a wire, as shown in the figure. At
the bottom of the wire, the bead is loaded against a spring with spring constant k =
1000 N/m. The spring is pulled back a distance of 15 cm from its uncompressed
length.
When the spring is released, the bead is launched up the wire having a curve
described by the equation
y = 1.5 sin (#)
ITX
where y is in meters, and L = 2.0 m.
What are the normal and tangential forces (magnitude and direction) acting on the
bead when it is at x = 0.70 m?
Transcribed Image Text:y
y= {x),
k
m
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