The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.4 98.1 96.5 96.3 99.8 96.4 97 99.4 96.7 98.3 97.1 Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 99% C.I. =

The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.4 98.1 96.5 96.3 99.8 96.4 97 99.4 96.7 98.3 97.1 Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 99% C.I. =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A poll was conducted that asked 1010 people how many books they had read in the past year. Results indicated that x= 10.5 books and s= 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Click the icon to view the table of areas under the t-distribution. Construct a 99% confidence interval for the mean number of books people read. (Use ascending order. Round to two decimal places as needed.)
Given below are the sodium contents in milligrams for seven brands of hot dogs rated as “very good” by Consumer Reports. Find a 99.9% confidence interval for the true mean amount of sodium for “very good” hotdogs. 400 470 350 365 270 550 530
A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00
A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480 college students showed that 23% of them had, or intended to, cheat on examinations. Find the 95% confidence interval for the population proportion. Round to four decimal places.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Find the margin of error for the 95% confidence interval used to estimate the population mean. Assume that the population has a normal distribution. A sociologist develops a test to measure attitudes towards public transportation, and 27 randomly selected subjects are given the test. Their mean score is 76.2 and their standard deviation is 21.4. O 6.77 O 8.07 O 8.47 8.44
In the construction of an 88% Confidence Interval for a population mean u, a has the value of
Construct the indicated confidence interval for the difference in proportions. Assume that the samples are Independent and that they have been randomly selected. A survey of randomly chosen adults found that 45% of the 231 women and 61% of the 275 men follow regular exercise programs. Construct a 95% confidence interval for the difference in the proportions of women and men who have regular exercise programs. O A. (-0.165, -0.155) OB. (0.052, 0.268 ) OC. (-0.246, -0.074) O D. (-0.267, -0.053) O E. (-0.250, -0.070 )
Determine the margin of error for the confidence interval for the mean: 16+1.5 The margin of error is
A surprising fact indicates that a small proportion of teens use a password on their mobile device. A poll chooses a simple random sample of 120 teens and asks if they use a password on their mobile device. The results showed that 56 of teens in our sample used a password on their mobile device. Find a 90 % confidence interval for the proportion of teens who use a password on their mobile device. Interpret your confidence interval.
A survey was conducted that asked 1016 people how many books they had read in the past year. Results indicated that x = 11.8 books and s = 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Interpret the interval. E Click the icon to view the table of critical t-values. Construct a 99% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete vour choice. (Use ascending order. Round to two decimal places as needed.) O A. If repeated samples are taken, 99% of them will have a sample mean between and. Table of Critical t-Values O B. There is a 99% probability that the true mean number of books read is between and. OC. There is 99% confidence that the population mean number of books read is between and . t-Distribution Area in Right Tail Degrees of Freedom 0.25 0.20 0.15 0.10 0025 00 0.01 0.005 0.0025 0.001 0.0005 1.376 1.963 1.061 1.386 0.978 1.250…