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The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.4 98.1 99.8 99.3 96.3 97.3 98.3 96.7 Assume body temperatures of adults are normally distributed. Based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 98% C.I. -

The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.4 98.1 99.8 99.3 96.3 97.3 98.3 96.7 Assume body temperatures of adults are normally distributed. Based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 98% C.I. -

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.4 98.1 99.8 99.3 96.3 97.3 98.3 96.7 Assume body temperatures of adults are normally distributed. Based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 98% C.I. =
Transcribed Image Text:The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.4 98.1 99.8 99.3 96.3 97.3 98.3 96.7 Assume body temperatures of adults are normally distributed. Based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 98% C.I. =
Expert Solution
Step 1: Given data :
xx2
96.49292.96
98.19623.61
99.89960.04
99.39860.49
96.39273.69
97.39467.29
98.39662.89
96.79350.89
sum for blank of straight X equals 782.2
sum for blank of straight X squared equals 76491.86
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