Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The body in the figure is pivoted at O. Three forces act on it in the directions shown: FA-5.80 N at point A, 9.40 m from O: F-15.0N at point B, 4.80 m from O; and Fe=19.0 N at point C, 1.40 m from O. Taking the clockwise direction to be negative, what is the net torque about O? Number Units

The body in the figure is pivoted at O. Three forces act on it in the directions shown: FA-5.80 N at point A, 9.40 m from O: F-15.0N at point B, 4.80 m from O; and Fe=19.0 N at point C, 1.40 m from O. Taking the clockwise direction to be negative, what is the net torque about O? Number Units

icon
Related questions
Question
### Net Torque Calculation The body in the figure is pivoted at point O. Three forces act on it in the directions shown: - \(F_A = 5.80 \, \text{N}\) at point A, which is 9.40 m from O. - \(F_B = 15.0 \, \text{N}\) at point B, which is 4.80 m from O. - \(F_C = 19.0 \, \text{N}\) at point C, which is 1.40 m from O. We are to determine the net torque about point O, considering the clockwise direction as negative. ### Diagram Explanation: The diagram displayed shows an irregularly shaped body pivoted at point O. - Point A is on the body with a force \(F_A\) acting in a direction specified in the diagram. - Point B is on the body with a force \(F_B\) acting in a different direction. - Point C is on the body with a force \(F_C\) acting in yet another direction. - Each force is shown with its respective angle and distance from O. ### Torque Calculation: 1. **Torque from \(F_A\) (Counterclockwise - positive direction):** - \( \tau_A = F_A \times d_A \times \sin(\theta_A) \) - \( d_A = 9.40 \, \text{m} \) - Assume \(\theta_A\) is the angle given relative to the lever arm. - Assume from diagram: \( \theta_A = 130^\circ \) 2. **Torque from \(F_B\) (Counterclockwise - positive direction):** - \( \tau_B = F_B \times d_B \times \sin(\theta_B) \) - \( d_B = 4.80 \, \text{m} \) - Assume \(\theta_B\) is the angle given relative to the lever arm. - Assume from diagram: \( \theta_B = 180^\circ - 60^\circ \) (120 degrees) 3. **Torque from \(F_C\) (Clockwise - negative direction):** - \( \tau_C = F_C \times d_C \times \sin(\theta_C) \) - \( d_C = 1.40 \, \text
Transcribed Image Text:### Net Torque Calculation The body in the figure is pivoted at point O. Three forces act on it in the directions shown: - \(F_A = 5.80 \, \text{N}\) at point A, which is 9.40 m from O. - \(F_B = 15.0 \, \text{N}\) at point B, which is 4.80 m from O. - \(F_C = 19.0 \, \text{N}\) at point C, which is 1.40 m from O. We are to determine the net torque about point O, considering the clockwise direction as negative. ### Diagram Explanation: The diagram displayed shows an irregularly shaped body pivoted at point O. - Point A is on the body with a force \(F_A\) acting in a direction specified in the diagram. - Point B is on the body with a force \(F_B\) acting in a different direction. - Point C is on the body with a force \(F_C\) acting in yet another direction. - Each force is shown with its respective angle and distance from O. ### Torque Calculation: 1. **Torque from \(F_A\) (Counterclockwise - positive direction):** - \( \tau_A = F_A \times d_A \times \sin(\theta_A) \) - \( d_A = 9.40 \, \text{m} \) - Assume \(\theta_A\) is the angle given relative to the lever arm. - Assume from diagram: \( \theta_A = 130^\circ \) 2. **Torque from \(F_B\) (Counterclockwise - positive direction):** - \( \tau_B = F_B \times d_B \times \sin(\theta_B) \) - \( d_B = 4.80 \, \text{m} \) - Assume \(\theta_B\) is the angle given relative to the lever arm. - Assume from diagram: \( \theta_B = 180^\circ - 60^\circ \) (120 degrees) 3. **Torque from \(F_C\) (Clockwise - negative direction):** - \( \tau_C = F_C \times d_C \times \sin(\theta_C) \) - \( d_C = 1.40 \, \text
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer