The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 4.00 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait times of 34 randomly selected calls. The mean wait time was calculated to be 4.61 minutes. Assuming the population standard deviation is 1.93 minutes, is there sufficient evidence to say that the mean wait time for customers is longer than 4.00 minutes with a 95% level of confidence? Step 3 of 3 : Draw a conclusion and interpret the decision. Answer A.We reject the null hypothesis and conclude that there is sufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes. B. We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes. C.We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes. D.We reject the null hypothesis and conclude that there is insufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 4.00 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait times of 34 randomly selected calls. The mean wait time was calculated to be 4.61 minutes. Assuming the population standard deviation is 1.93 minutes, is there sufficient evidence to say that the mean wait time for customers is longer than 4.00 minutes with a 95% level of confidence?

Step 3 of 3 :

Draw a conclusion and interpret the decision.

Answer

A.We reject the null hypothesis and conclude that there is sufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes.
B. We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes.

C.We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes.
D.We reject the null hypothesis and conclude that there is insufficient evidence at a 95% level of confidence to support the claim that the mean wait time is longer than 4.00 minutes.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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