The blood alcohol C2H5OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr3+ (aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2O72-) is orange in solution, and the Cr3+ ion is green. The unbalanced redox equation is:Cr2O72-(aq) + C2H5OH(aq) --> Cr3+(aq) +CO2(g)If 17.11 mL of 0.0806 M potassium dichromate solution is required to titrate 15.9 g of blood plasma, determine the mass percent of alcohol in the blood.

The balanced chemical reaction is given below.

Answered: The blood alcohol C2H5OH level can be…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The blood alcohol C₂H₅OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr³⁺ (aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr₂O₇^2-) is orange in solution, and the Cr³⁺ ion is green. The unbalanced redox equation is:

Cr₂O₇^2-(aq) + C₂H₅OH(aq) --> Cr³⁺(aq) +CO₂(g)

If 17.11 mL of 0.0806 M potassium dichromate solution is required to titrate 15.9 g of blood plasma, determine the mass percent of alcohol in the blood.

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