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The blocks shown are being pulled up the incline by a force P = 500N. Determine the acceleration of block B. Neglect friction and weights of the pulleys. Use WA = 75kg, We= 100kg and f = 0.25.

The blocks shown are being pulled up the incline by a force P = 500N. Determine the acceleration of block B. Neglect friction and weights of the pulleys. Use WA = 75kg, We= 100kg and f = 0.25.

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Answer:  aB = 0.501m/s2 

 

I did attached an example. Thank you in advance

Example 3: For the figure shown, solve for the acceleration of block B. Neglect the weights of the pulleys and assumed them frictionless. Use WA =300N and WB =400N. Solution: TB Wa 400a Block B: ΣFy : TB- 400 2g 2(9.81) TB = 20.387a + 400 Wa 2g %3D B wa Block A: ΣFy 300a : 300 - TA = %3D 9.81 WB TA = 300 – 30.581a B Upper Pulley: 2 TA = TB Wa 2(300-30.581a) = 20.387a+400 %3D 81.549a=200, a= 2.453m/s? a Then: aB = 1.227m/s? ans. 2
Transcribed Image Text:Example 3: For the figure shown, solve for the acceleration of block B. Neglect the weights of the pulleys and assumed them frictionless. Use WA =300N and WB =400N. Solution: TB Wa 400a Block B: ΣFy : TB- 400 2g 2(9.81) TB = 20.387a + 400 Wa 2g %3D B wa Block A: ΣFy 300a : 300 - TA = %3D 9.81 WB TA = 300 – 30.581a B Upper Pulley: 2 TA = TB Wa 2(300-30.581a) = 20.387a+400 %3D 81.549a=200, a= 2.453m/s? a Then: aB = 1.227m/s? ans. 2
Problem 3: The blocks shown are being pulled up the incline by a force P = 500N. Determine the acceleration of block B. Neglect friction and weights of the pulleys. Use WA = 75kg, We= 100kg and f = 0.25.
Transcribed Image Text:Problem 3: The blocks shown are being pulled up the incline by a force P = 500N. Determine the acceleration of block B. Neglect friction and weights of the pulleys. Use WA = 75kg, We= 100kg and f = 0.25.
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