The block is at rest as shown. What is the peiod of the oscillation if the block is pulled down by 10 cm, in seconds? Use g = 10 m/s2.Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. This image depicts a physics setup for studying Hooke's Law, demonstrating the relationship between force and the extension of a spring.**Diagram Explanation:**1. **Spring Setup:** - The spring is attached to a fixed support at the top. - A mass of 100 grams is suspended at the bottom of the spring, causing it to stretch due to gravitational force.2. **Ruler Measurement:** - A vertical ruler is placed next to the spring to measure its extension. - The ruler is marked in centimeters, ranging from 0 cm at the top to 100 cm at the bottom. - The initial unstretched length of the spring appears to align with the 50 cm mark on the ruler.3. **Lines of Reference:** - A blue dashed line represents the original position of the spring before the mass was added, aligning with the 50 cm mark. - A green dashed line indicates the new equilibrium position of the spring after adding the 100 g mass, aligning with approximately the 78 cm mark.Through this setup, students can observe how adding weight to the spring affects its extension, illustrating Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension from the equilibrium position, \( F = kx \), where \( k \) is the spring constant and \( x \) is the displacement.

Name: The block is at rest as shown. What is the peiod of the oscillation if
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: The block is at rest as shown. What is the peiod of the oscillation if the block is pulled down by 10 cm, in seconds? Use g = 10 m/s2.Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not includ

Given Mass m = 100 g = 0.1 kg Extension x = 10 cm = 0.1 m According to Hook's law F = kx mg = kx k = mg/x = 0.1 × 10 /0.1 = N/m Time period T = 2π (m/k)1/2 T = 2× 3.14 (0.1/10)1/2 = 0.63 sec