The block has mass M and rests on a surface for which thecoefficients of static and kinetic friction are uandHe respectively. Aforce F kt is applied to the cable. Velocity of block att= 2 sec is v m/s. Then value of v is. Given : M = 24 kg, k 60 N/s?, u= 0.5, µ, = 0.4%3D

Given, v(t=2)=vm/sM=24 kgk=60 N/s2μs=0.5μk=0.4

The block has mass M and rests on a surface for which the coefficients of static and kinetic friction are u, and u, respectively. A force F kt2 is applied to the cable. Velocity of block at t 2 sec is v m/s. Then value of v is. Given : M 24 kg, k 60 N/s?, u = 0.5, µ = 0.4 %3D %3D M

The block has mass M and rests on a surface for which the coefficients of static and kinetic friction are u, and u, respectively. A force F kt2 is applied to the cable. Velocity of block at t 2 sec is v m/s. Then value of v is. Given : M 24 kg, k 60 N/s?, u = 0.5, µ = 0.4 %3D %3D M

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Basic Terminology in Mechanics

The area of science and mathematics concerned the motion of the objects, the relation between the force matter, and motion if specified. Forces exerted over the objects result in displacements or changes in the position of an object concerning its environment. This branch of physics keeps its roots in Ancient Greece in the form of the scripts of Aristotle and Archimedes.

Question

The block has mass M and rests on a surface for which the
coefficients of static and kinetic friction are u
and
He respectively. A
force F kt is applied to the cable. Velocity of block at
t= 2 sec is v m/s. Then value of v is. Given : M = 24 kg, k 60 N/s?, u
= 0.5, µ, = 0.4
%3D

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