The Biot-Savart law gives the magnetic field due to a very short segment of current I:Ho I dsxîp2dB =where ds is a vector that points in the direction of the current with magnitude equal to the length of the smallsegment and r is the vector from the small current segment to the point P where you want to find the-2.5 m j and ds = (-0.04 i – 0.03 j) m and I = 4A What is the magnetic field dB atpoint P due to just the small wire segment ? (The Biot-Savart law holds only if the segment ds is infinitetessimallysmall but should be a good approximation here since ds < r).dsI+yP+x+z (out) 2.56x10-9 TkO -1.28x10-9 TKO 1.92x109 T ÂO -3.20x10-9 T k-2.56x10-9 T kO -1.92x10-9 TK

magnetic field(dB) at point P. given, r→=-2.5 m j^ds→=(-0.04 i^-0.03 j^ ) mcurrentI=4 A

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