The Binomial Theorem says that for any positive integer n and any real numbers x and y: Σ-o (R)aty"-k = (z + y)" kn-k (x + y)" k=0 Use the binomial theorem to determine the value of ΣR=o (R) (-3)* k=0

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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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discrete math

## Understanding the Binomial Theorem

The Binomial Theorem states that for any positive integer \( n \) and any real numbers \( x \) and \( y \):

\[
\sum_{k=0}^n \binom{n}{k} x^k y^{n-k} = (x + y)^n
\]

Where \(\binom{n}{k}\) denotes a binomial coefficient (also known as "n choose k").

### Application of the Binomial Theorem

Use the Binomial Theorem to determine the value of the following summation:

\[
\sum_{k=0}^n \binom{n}{k} (-3)^k
\]

### Multiple Choice Options

- \(3^n\)
- \(2^n\)
- None of the given choices.
- \((-3)^n\)
- \(4^n\)
- \((-2)^n\)
- \((-4)^n\)

### Explanation:

To determine which expression matches the given summation, apply the binomial theorem again. In the given summation, set \(x = -3\) and \(y = 1\):

\[
\sum_{k=0}^n \binom{n}{k} (-3)^k = (1 + (-3))^n = (-2)^n
\]

Therefore, the correct answer is:

\[
\boxed{(-2)^n}
\]

### Answer:
\(\mathbf{(-2)^n}\)

This content is designed to help students understand how to apply the binomial theorem to solve problems involving binomial expansions.
Transcribed Image Text:## Understanding the Binomial Theorem The Binomial Theorem states that for any positive integer \( n \) and any real numbers \( x \) and \( y \): \[ \sum_{k=0}^n \binom{n}{k} x^k y^{n-k} = (x + y)^n \] Where \(\binom{n}{k}\) denotes a binomial coefficient (also known as "n choose k"). ### Application of the Binomial Theorem Use the Binomial Theorem to determine the value of the following summation: \[ \sum_{k=0}^n \binom{n}{k} (-3)^k \] ### Multiple Choice Options - \(3^n\) - \(2^n\) - None of the given choices. - \((-3)^n\) - \(4^n\) - \((-2)^n\) - \((-4)^n\) ### Explanation: To determine which expression matches the given summation, apply the binomial theorem again. In the given summation, set \(x = -3\) and \(y = 1\): \[ \sum_{k=0}^n \binom{n}{k} (-3)^k = (1 + (-3))^n = (-2)^n \] Therefore, the correct answer is: \[ \boxed{(-2)^n} \] ### Answer: \(\mathbf{(-2)^n}\) This content is designed to help students understand how to apply the binomial theorem to solve problems involving binomial expansions.
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