The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m 0.5 m E .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg
The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m 0.5 m E .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The bent rod in Fig. a is supported at A by a journal bearing, at D by
a ball-and-socket joint, and at B by means of cable BC. Using only
one equilibrium equation, obtain a direct solution for the tension in
cable BC. The bearing at A is capable of exerting force components
only in the z and y directions since it is properly aligned on the shaft.
In other words, no couple moments are required at this support.
1m
B
0.5 m
E
.Free-Body Diagram. As shown in Fig. b, there are six unknowns
0.5 m
Equations of Equilibrium. The cable tension Tg may be obtained
directly by summing moments about an axis that passes through
points D and A. Why?
100 kg
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