Wide-Flange Sections or W Shapes-U.S. Customary UnitsDesignation AW24 x 9424 x 7624 × 6824 x 55W21 x 6821 x 6221 x 5021 x 44W18 x 5518 x 5018 x 4018 x 35W16 x 5716 x 5016 x 4016 x 31W14 x 6814 x 5314 x 4814 x 3414 x 3014 x 2614 x 22Answer:Area Depthd(a) Smin =(b) Wi(c) W = iin.²27.722.420.116.220.018.314.713.016.214.711.810.316.814.711.89.1320.015.614.110.0in.24.323.923.723.621.121.020.820.718.118.017.917.716.416.316.015.914.013.913.814.08.85 13.87.6913.96.4913.7Webthicknesstwin.0.5150.4400.4150.395X ilb0.4300.4000.3800.3500.3900.3550.3150.3000.4300.3800.3050.275in.³0.4150.3700.3400.2850.2700.2550.230Flange Flangewidththicknessbgtsin.9.078.998.977.018.278.246.536.507.537.506.026.007.127.077.005.5310.08.068.036.756.735.035.00in.0.8750.6800.5850.5050.6850.6150.5350.4500.6300.5700.5250.4250.7150.6300.5050.4400.7200.6600.5950.4550.3850.4200.335in.4270021001830135014801330984843890800612510758659518375722541484340291245199Sxin.322217615411414012794.581.698.388.968.457.692.281.064.747.210377.870.248.642.035.329.0Txin.9.879.699.559.118.608.548.188.067.417.387.217.046.726.686.636.415.855.835.735.655.54I,in.4410982.570.429.164.757.524.920.744.940.119.115.36.01 1215.8943.137.228.912.457.751.423.319.68.917.00Syin.³24.018.415.78.3015.714.07.646.3711.910.76.355.1212.110.58.254.4924.214.312.86.915.823.552.80Tyin.1.981.921.871.341.801.771.301.261.671.651.271.221.601.591.571.172.461.921.911.531.491.081.04 The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 12.9 ksi. Assume P = 51 kips,L₁= 2.1 ft, and L2 = 6.3 ft.(a) Determine the minimum section modulus required for this beam.(b) From the table below, select the lightest W shape that can be used for this beam.(c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)?PBL2C2Wide-Flange Sections or W Shapes-U.S. Customary UnitsDXdXIw

Allowable bending stress = 12.9 ksi Determinea. Minimum section modulus. b. Lightest W shape…

The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 12.9 ksi. Assume P = 51 ki L₁= 2.1 ft, and L2 = 6.3 ft. (a) Determine the minimum section modulus required for this beam. (b) From the table below, select the lightest W shape that can be used for this beam. (c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)? P B L2 2 Wide-Flange Sections or W Shapes-U.S. Customary Units D X d X Tw

The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 12.9 ksi. Assume P = 51 ki L₁= 2.1 ft, and L2 = 6.3 ft. (a) Determine the minimum section modulus required for this beam. (b) From the table below, select the lightest W shape that can be used for this beam. (c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)? P B L2 2 Wide-Flange Sections or W Shapes-U.S. Customary Units D X d X Tw

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Wide-Flange Sections or W Shapes-U.S. Customary Units
Designation A
W24 x 94
24 x 76
24 × 68
24 x 55
W21 x 68
21 x 62
21 x 50
21 x 44
W18 x 55
18 x 50
18 x 40
18 x 35
W16 x 57
16 x 50
16 x 40
16 x 31
W14 x 68
14 x 53
14 x 48
14 x 34
14 x 30
14 x 26
14 x 22
Answer:
Area Depth
d
(a) Smin =
(b) Wi
(c) W = i
in.²
27.7
22.4
20.1
16.2
20.0
18.3
14.7
13.0
16.2
14.7
11.8
10.3
16.8
14.7
11.8
9.13
20.0
15.6
14.1
10.0
in.
24.3
23.9
23.7
23.6
21.1
21.0
20.8
20.7
18.1
18.0
17.9
17.7
16.4
16.3
16.0
15.9
14.0
13.9
13.8
14.0
8.85 13.8
7.69
13.9
6.49
13.7
Web
thickness
tw
in.
0.515
0.440
0.415
0.395
X i
lb
0.430
0.400
0.380
0.350
0.390
0.355
0.315
0.300
0.430
0.380
0.305
0.275
in.³
0.415
0.370
0.340
0.285
0.270
0.255
0.230
Flange Flange
width
thickness
bg
ts
in.
9.07
8.99
8.97
7.01
8.27
8.24
6.53
6.50
7.53
7.50
6.02
6.00
7.12
7.07
7.00
5.53
10.0
8.06
8.03
6.75
6.73
5.03
5.00
in.
0.875
0.680
0.585
0.505
0.685
0.615
0.535
0.450
0.630
0.570
0.525
0.425
0.715
0.630
0.505
0.440
0.720
0.660
0.595
0.455
0.385
0.420
0.335
in.4
2700
2100
1830
1350
1480
1330
984
843
890
800
612
510
758
659
518
375
722
541
484
340
291
245
199
Sx
in.3
222
176
154
114
140
127
94.5
81.6
98.3
88.9
68.4
57.6
92.2
81.0
64.7
47.2
103
77.8
70.2
48.6
42.0
35.3
29.0
Tx
in.
9.87
9.69
9.55
9.11
8.60
8.54
8.18
8.06
7.41
7.38
7.21
7.04
6.72
6.68
6.63
6.41
5.85
5.83
5.73
5.65
5.54
I,
in.4
4
109
82.5
70.4
29.1
64.7
57.5
24.9
20.7
44.9
40.1
19.1
15.3
6.01 121
5.89
43.1
37.2
28.9
12.4
57.7
51.4
23.3
19.6
8.91
7.00
Sy
in.³
24.0
18.4
15.7
8.30
15.7
14.0
7.64
6.37
11.9
10.7
6.35
5.12
12.1
10.5
8.25
4.49
24.2
14.3
12.8
6.91
5.82
3.55
2.80
Ty
in.
1.98
1.92
1.87
1.34
1.80
1.77
1.30
1.26
1.67
1.65
1.27
1.22
1.60
1.59
1.57
1.17
2.46
1.92
1.91
1.53
1.49
1.08
1.04

The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 12.9 ksi. Assume P = 51 kips,
L₁= 2.1 ft, and L2 = 6.3 ft.
(a) Determine the minimum section modulus required for this beam.
(b) From the table below, select the lightest W shape that can be used for this beam.
(c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)?
P
B
L2
C
2
Wide-Flange Sections or W Shapes-U.S. Customary Units
D
X
d
X
Iw

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