The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 21.6 ksi. Assume P = 47 kips, L₁= 2.1 ft, and L₂ = 6.3 ft. (a) Determine the minimum section modulus required for this beam. (b) From the table below, select the lightest W shape that can be used for this beam. (c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)? Desigua X 24×35 W21-58 21.50 21-44 U Vaxs 88-50 lb 18-35 WW.ST M 14.33 Ha 14.M L₁ 14-3 14x22 Ama Expe A i (c) W= i B 21.3 343 80545 Com 201 0415 182 21 0315 116 267 143 DE IKK 179 Answer: 4 2021304M 143 219 04 8.24 DAN 147 BE 6.30 4.35 034 9354 (a) Smin = i in.³ (b) W i 36-30 43159629 WHIM 20140415 8345 10.3 13 6.300 147 143 AN HE AIM 150 0359 sin 4 EW AND 700 s 327 BMD WAS 150 8.500 an BAS 712 1715 144 ...O BEW 6.300 107 BAR INF 6.35 THE 6.35 5.38 840 we Sp 116 141 138 630 P H 148 820 619 KAS 118 313 0279 260194299 6.49 137 023 AVC L₂ akine 500 RETS BUD 8535 are 8.40 BAR BAD 2300 & 176 ww 154 1950 11 140 100 325 A P 718 3802 RA MY 22 641 L₁ 987 5.89 BL 4.35 764 15.3 911 LW * 5.89 4₂ 147 37.5 15.3 41 32 121 12.3 140 254 319 167 SAN AM 5.34 532 121 39 124 LUR 312 143 D 513 383 233 5.75 146 510 146 20 196 8.90 1.34 8.50 KT 1.37 117 1.30 168 242 24 LM

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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The beam shown will be constructed from
a standard steel W-shape using an
allowable bending stress of 21.6 ksi.
Assume P = 47 kips, L₁= 2.1 ft, and L₂ = 6.3
ft.
(a) Determine the minimum section
modulus required for this beam.
(b) From the table below, select the
lightest W shape that can be used for this
beam.
(c) What is the total weight of the steel
beam itself (i.e., not including the loads
that are carried by the beam)?
X
Wide-Flange Sections or W Shapes U.S. Customery Units
Hay Flag
Area Depth with thick
By
9
Designation A
***
lb
¹7
W21-68
21x62
21 - 50
21 × 44
Wis: 15
1850
4
in² in in
12494 213 243 0.545
24 x 76
22.4
239 9.449
31.1 237
0415
062 236 0:395
at
W16 - 31
16x30
16x40
16x31
16 x 31
W14-68
21
21.1
143 218
147 208 0:389
118 303
9359
0:30
142 143
1413 119
9.344
0355
LEK 179
0345
1836 103 177 $500
0300
14×48
14x34
14x30
14x36
Answer:
B
(a) Smin =
i
in.³
(b) W
i
i
(c) W =
i
P
Web
9430
0400
164 0.438
0.300
0305
1
in
907
8.99
LAX
7.33
730
Am
6.002
as
7.01 0.505
8.27
BAK
8.34
6.33
6.30
50
6.00
ww
14.3 163
LK 16
4.33 159
20
14.8
0275
was
0:415 100
116 119 0339
HI
14
138 0349
100
8.45
0 148 0285
*AS 118
0:25
249 119
769
0255
137
0239
7:12
701
700
THE
5.33
L₂
10%
in
0.875
nevn
6.33
501
500
D
sivn
01.335
11450
BAD
wam
01.570
wwwww
11425
Chu
0713
1700
KOO (1660
0.595
8630
0505
040
6.75 01-455
(B
0.40
05
0.335
4
a
2700
2000
14X1
1350
1490
113
954
843
20
800
412
DIS
me
758
6.59
318
375
722
341
454
341
291
245
5₂
in
222
9.87
176 5.89
154
9.35
931
LM
24
HI
C
140
in
121
STA
vix
943
816
*
16.3 241
200
18.9
w
684
WEN
14%
NT
114
8.34
K.16
ww
10:2 672
42.0
36.3
7.38
ww
7:21
7:04
pe
www
643
641
L₁
4,
in W?
in
1.59
109 2411
102.5
70.4 15.7 100
1.92
291
1.30
134
64.7
15.7
IND
37.5 1411
177
24.9
317
449
Day
4.1
IN1
19.1
153
'y
201
6.37
119
11.9
10.7
#06 5.83 233
6.35
5.12
401 12.1
10.5
372
339
114
3.25
off
76.2 5.85 514 128
-x
X
D
S
1.30
126
167
ww
1.45
In
1.27
100
6.00 121
242 246
718 5.99 51.3 14.3 4.92
LM
ww
822
160
1.39
1.37
8.17
1.33
AMI
5.11 196 5.80 149
565 891 1.46 LOG
7:00
5.54
LDI
Transcribed Image Text:The beam shown will be constructed from a standard steel W-shape using an allowable bending stress of 21.6 ksi. Assume P = 47 kips, L₁= 2.1 ft, and L₂ = 6.3 ft. (a) Determine the minimum section modulus required for this beam. (b) From the table below, select the lightest W shape that can be used for this beam. (c) What is the total weight of the steel beam itself (i.e., not including the loads that are carried by the beam)? X Wide-Flange Sections or W Shapes U.S. Customery Units Hay Flag Area Depth with thick By 9 Designation A *** lb ¹7 W21-68 21x62 21 - 50 21 × 44 Wis: 15 1850 4 in² in in 12494 213 243 0.545 24 x 76 22.4 239 9.449 31.1 237 0415 062 236 0:395 at W16 - 31 16x30 16x40 16x31 16 x 31 W14-68 21 21.1 143 218 147 208 0:389 118 303 9359 0:30 142 143 1413 119 9.344 0355 LEK 179 0345 1836 103 177 $500 0300 14×48 14x34 14x30 14x36 Answer: B (a) Smin = i in.³ (b) W i i (c) W = i P Web 9430 0400 164 0.438 0.300 0305 1 in 907 8.99 LAX 7.33 730 Am 6.002 as 7.01 0.505 8.27 BAK 8.34 6.33 6.30 50 6.00 ww 14.3 163 LK 16 4.33 159 20 14.8 0275 was 0:415 100 116 119 0339 HI 14 138 0349 100 8.45 0 148 0285 *AS 118 0:25 249 119 769 0255 137 0239 7:12 701 700 THE 5.33 L₂ 10% in 0.875 nevn 6.33 501 500 D sivn 01.335 11450 BAD wam 01.570 wwwww 11425 Chu 0713 1700 KOO (1660 0.595 8630 0505 040 6.75 01-455 (B 0.40 05 0.335 4 a 2700 2000 14X1 1350 1490 113 954 843 20 800 412 DIS me 758 6.59 318 375 722 341 454 341 291 245 5₂ in 222 9.87 176 5.89 154 9.35 931 LM 24 HI C 140 in 121 STA vix 943 816 * 16.3 241 200 18.9 w 684 WEN 14% NT 114 8.34 K.16 ww 10:2 672 42.0 36.3 7.38 ww 7:21 7:04 pe www 643 641 L₁ 4, in W? in 1.59 109 2411 102.5 70.4 15.7 100 1.92 291 1.30 134 64.7 15.7 IND 37.5 1411 177 24.9 317 449 Day 4.1 IN1 19.1 153 'y 201 6.37 119 11.9 10.7 #06 5.83 233 6.35 5.12 401 12.1 10.5 372 339 114 3.25 off 76.2 5.85 514 128 -x X D S 1.30 126 167 ww 1.45 In 1.27 100 6.00 121 242 246 718 5.99 51.3 14.3 4.92 LM ww 822 160 1.39 1.37 8.17 1.33 AMI 5.11 196 5.80 149 565 891 1.46 LOG 7:00 5.54 LDI
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